this.axes = axes;
    int[] axesSizeProduct = new int[axes.size() + 1];
    axesSizeProduct[axes.size()] = 1;
    try {
      for (int i = axes.size() - 1; i >= 0; i--) {
        axesSizeProduct[i] = Math.multiplyExact(axesSizeProduct[i + 1], axes.get(i).size());
      }
    } catch (ArithmeticException e) {
      throw new IllegalArgumentException(
          "Cartesian product too large; must have size at most Integer.MAX_VALUE");
    }

   *
   * <p><b>Note:</b> this method is now unnecessary and should be treated as deprecated; use {@link
   * Math#multiplyExact(long, long)} instead. Note that if both arguments are {@code int} values,
   * writing {@code Math.multiplyExact(a, b)} will call the {@link Math#multiplyExact(int, int)}
   * overload, not {@link Math#multiplyExact(long, long)}. Also note that multiplying two {@code

    this.k = k;
    checkArgument(k >= 0, "k (%s) must be >= 0", k);
    checkArgument(k <= Integer.MAX_VALUE / 2, "k (%s) must be <= Integer.MAX_VALUE / 2", k);
    this.buffer = (T[]) new Object[Math.multiplyExact(k, 2)];
    this.bufferSize = 0;
    this.threshold = null;
  }

  /**
   * Adds {@code elem} as a candidate for the top {@code k} elements. This operation takes amortized
   * O(1) time.
   */

       */
      @SuppressWarnings("EnumOrdinal")
      Strategy strategy = BloomFilterStrategies.values()[strategyOrdinal];

      LockFreeBitArray dataArray = new LockFreeBitArray(Math.multiplyExact(dataLength, 64L));
      for (int i = 0; i < dataLength; i++) {
        dataArray.putData(i, din.readLong());
      }

      return new BloomFilter<>(dataArray, numHashFunctions, funnel, strategy);