= $('body')\n      $body.addClass(CLASS_NAME_IFRAME_MODE)\n\n      if (this._config.autoDarkMode) {\n        $body.addClass('dark-mode')\n      }\n    }\n  }\n\n  _navScroll(offset) {\n    const leftPos = $(SELECTOR_TAB_NAVBAR_NAV).scrollLeft()\n    $(SELECTOR_TAB_NAVBAR_NAV).animate({ scrollLeft: (leftPos + offset) }, 250, 'linear')\n  }\n\n  _setupListeners() {\n    $(window).on('resize', () => {\n      setTimeout(() => {\n        this._fixHeight()\n      }, 1)\n    })\n    if ($(SELECTOR_CONTE...

      }
    }

    // In theory, wildcard rules are not restricted to having the wildcard in the leftmost position.
    // In practice, wildcards are always in the leftmost position. For now, this implementation
    // cheats and does not attempt every possible permutation. Instead, it only considers wildcards
    // in the leftmost position. We assert this fact when we generate the public suffix file. If

  }

  /**
   * Performs a lookup for the public suffix of the given labels, considering all public suffix
   * types. Returns the index of the leftmost label in the public suffix, or -1 if no match found.
   *
   * @param labels the domain labels, from left to right.
   * @return the index of the leftmost label in the public suffix, or -1 if not found.
   */
  public int findSuffixIndex(List<String> labels) {

  private static final String S0 = "3";
  private static final String S1 = "Ninety five";
  private static final String S2 = "44 one million";
  private static final String S3 = "Lowly laundry lefties";
  private static final String S4 = "89273487U#*&#";
  private static final Double D0 = 9.234d;
  private static final Double D1 = -1.2e55;

  @Benchmark
  int hashString_2(int reps) {
    int dummy = 0;

  private static final String S0 = "3";
  private static final String S1 = "Ninety five";
  private static final String S2 = "44 one million";
  private static final String S3 = "Lowly laundry lefties";
  private static final String S4 = "89273487U#*&#";
  private static final Double D0 = 9.234d;
  private static final Double D1 = -1.2e55;

  @Benchmark
  int hashString_2(int reps) {
    int dummy = 0;

   */
  private fun assertWildcardRule(rule: String) {
    check(rule.startsWith(WILDCARD_CHAR)) {
      """Wildcard Assertion Failure: '$rule'
A wildcard rule was added with a wildcard that is not in leftmost position! We'll need to change the ${PublicSuffixDatabase::class.java.name} to handle this."""
    }
    check(rule.indexOf(WILDCARD_CHAR, 1) == -1) {
      """Wildcard Assertion Failure: '$rule'

g(e){return le({},e,{right:e.left+e.width,bottom:e.top+e.height})}function u(e){var o={};try{if(r(10)){o=e.getBoundingClientRect();var n=l(e,'top'),i=l(e,'left');o.top+=n,o.left+=i,o.bottom+=n,o.right+=i}else o=e.getBoundingClientRect()}catch(t){}var p={left:o.left,top:o.top,width:o.right-o.left,height:o.bottom-o.top},s='HTML'===e.nodeName?c(e.ownerDocument):{},d=s.width||e.clientWidth||p.width,a=s.height||e.clientHeight||p.height,f=e.offsetWidth-d,h=e.offsetHeight-a;if(f||h){var u=t(e);f-=m(u,'x'),h-=...

   * k) worst case.
   */
  private void trim() {
    int left = 0;
    int right = 2 * k - 1;

    int minThresholdPosition = 0;
    // The leftmost position at which the greatest of the k lower elements
    // -- the new value of threshold -- might be found.

    int iterations = 0;
    int maxIterations = IntMath.log2(right - left, RoundingMode.CEILING) * 3;

 *    no pinning will be enforced if additional prefixes are present, or if no prefixes are present.
 *
 * Note that any other form is unsupported. You may not use asterisks in any position other than
 * the leftmost label.
 *
 * If multiple patterns match a hostname, any match is sufficient. For example, suppose pin A
 * applies to `*.publicobject.com` and pin B applies to `api.publicobject.com`. Handshakes for

O código de saída, o fechamento automático da `Session` em:

{* ../../docs_src/dependencies/tutorial013_an_py310.py ln[19:21] *}

...seria executado depois que a resposta terminar de enviar os dados lentos:

{* ../../docs_src/dependencies/tutorial013_an_py310.py ln[30:38] hl[31:33] *}

Mas como `generate_stream()` não usa a sessão do banco de dados, não é realmente necessário manter a sessão aberta enquanto envia a resposta.