checkMessage(
        expected, "OtherOrder.FIRST -> MyOrder.THIRD", "MyOrder.THIRD -> OtherOrder.FIRST");
    lockA.lock();
    lock01.unlock();
    lockB.lock();
    lockA.unlock();

    expected = assertThrows(PotentialDeadlockException.class, () -> lock01.lock());
    checkMessage(
        expected, "LockB -> OtherOrder.FIRST", "LockA -> LockB", "OtherOrder.FIRST -> LockA");
  }

    int len = sequence.length();
    int first;
    int last;

    for (first = 0; first < len; first++) {
      if (!matches(sequence.charAt(first))) {
        break;
      }
    }
    for (last = len - 1; last > first; last--) {
      if (!matches(sequence.charAt(last))) {
        break;
      }
    }

    return sequence.subSequence(first, last + 1).toString();
  }

  /**

      ImmutableSortedSet.Builder<String> builder = ImmutableSortedSet.orderedBy(comparator);
      builder.add(BEFORE_FIRST);
      builder.add(BEFORE_FIRST_2);
      builder.add(elements);
      builder.add(AFTER_LAST);
      builder.add(AFTER_LAST_2);
      return builder
          .build()
          .subSet(BEFORE_FIRST_2, AFTER_LAST_2)
          .asList()
          .subList(1, elements.length + 1);
    }
  }

   * as equal, the first is returned.
   *
   * <p>The recommended solution for finding the {@code maximum} of some values depends on the type
   * of your data and the number of elements you have. Read more in the Guava User Guide article on
   * <a href="https://github.com/google/guava/wiki/CollectionUtilitiesExplained#comparators">{@code
   * Comparators}</a>.
   *

    @Override
    public int compare(@Nullable String first, @Nullable String second) {
      if (first == second) {
        return 0;
      } else if (first == null) {
        return -1;
      } else if (second == null) {
        return 1;
      } else if (first.length() != second.length()) {
        return first.length() - second.length();
      } else {
        return first.compareTo(second);
      }
    }
  }

    int len = sequence.length();
    int first;
    int last;

    for (first = 0; first < len; first++) {
      if (!matches(sequence.charAt(first))) {
        break;
      }
    }
    for (last = len - 1; last > first; last--) {
      if (!matches(sequence.charAt(last))) {
        break;
      }
    }

    return sequence.subSequence(first, last + 1).toString();
  }

  /**

    return Tables.transformValues(original, FIRST_CHARACTER);
  }

  @Override
  protected Map<String, Map<Integer, Character>> makePopulatedMap() {
    Table<Integer, String, String> table = HashBasedTable.create();
    table.put(1, "foo", "apple");
    table.put(1, "bar", "banana");
    table.put(3, "foo", "cat");
    return Tables.transformValues(table, FIRST_CHARACTER).columnMap();
  }

    /**
     * Adds a repository to use for subsequent resolution requests. The order in which repositories are added matters,
     * repositories that were added first should also be searched first. When multiple repositories with the same
     * identifier are added, only the first repository being added will be used.
     *
     * @param repository The repository to add to the internal search chain, must not be {@code null}.

   *
   * @param first the first array of elements to concatenate
   * @param second the second array of elements to concatenate
   * @param type the component type of the returned array
   */
  @GwtIncompatible // Array.newInstance(Class, int)
  public static <T extends @Nullable Object> T[] concat(
      T[] first, T[] second, Class<@NonNull T> type) {

   * first specified. That is, if multiple elements are {@linkplain Object#equals equal}, all except
   * the first are ignored.
   */
  public static <E> ImmutableSet<E> of(E e1, E e2) {
    return construct(2, e1, e2);
  }

  /**
   * Returns an immutable set containing the given elements, minus duplicates, in the order each was