testsuite.attrib = suite_attrib
    indent_xml(testsuites)

  tree = ElemTree.ElementTree(testsuites)
  file_path = os.path.join(output_path)
  with open(file_path, 'wb') as f:
    f.write(b'<?xml version="1.0"?>\n')
    tree.write(f)
    if verbose:
      print(f'\nWrote XML with Bazel invocation results to {file_path}')


def print_invocation_results(result_store_dict: ResultDictType):

👆 👩‍💻 👆 🔜 🤚 🎻 📨 💖:

```JSON
{
  "model_name": "alexnet",
  "message": "Deep Learning FTW!"
}
```

## ➡ 🔢 ⚗ ➡

➡️ 💬 👆 ✔️ *➡ 🛠️* ⏮️ ➡ `/files/{file_path}`.

✋️ 👆 💪 `file_path` ⚫️ 🔌 *➡*, 💖 `home/johndoe/myfile.txt`.

, 📛 👈 📁 🔜 🕳 💖: `/files/home/johndoe/myfile.txt`.

### 🗄 🐕‍🦺

🗄 🚫 🐕‍🦺 🌌 📣 *➡ 🔢* 🔌 *➡* 🔘, 👈 💪 ↘️ 😐 👈 ⚠ 💯 & 🔬.

```JSON
{
  "model_name": "alexnet",
  "message": "Deep Learning FTW!"
}
```

## Parameter path berisi path

Misalkan terdapat *operasi path* dengan path `/files/{file_path}`.

Tetapi anda memerlukan `file_path` itu berisi *path*, seperti like `home/johndoe/myfile.txt`.

Sehingga URL untuk file tersebut akan seperti: `/files/home/johndoe/myfile.txt`.

### Dukungan OpenAPI

```JSON
{
  "model_name": "alexnet",
  "message": "Deep Learning FTW!"
}
```

## Path-параметры, содержащие пути

Предположим, что есть *операция пути* с путем `/files/{file_path}`.

Но вам нужно, чтобы `file_path` сам содержал *путь*, например, `home/johndoe/myfile.txt`.

Тогда URL для этого файла будет такой: `/files/home/johndoe/myfile.txt`.

### Поддержка OpenAPI

```JSON
{
  "model_name": "alexnet",
  "message": "Deep Learning FTW!"
}
```

## Pfad Parameter die Pfade enthalten

Angenommen, Sie haben eine *Pfadoperation* mit einem Pfad `/files/{file_path}`.

Aber `file_path` soll selbst einen *Pfad* enthalten, etwa `home/johndoe/myfile.txt`.

Sprich, die URL für diese Datei wäre etwas wie: `/files/home/johndoe/myfile.txt`.

### OpenAPI Unterstützung

  "model_name": "alexnet",
  "message": "Deep Learning FTW!"
}
```

## Parâmetros de rota que contém caminhos

Digamos que você tenha uma *operação de rota* com uma rota `/files/{file_path}`.

Mas você precisa que o próprio `file_path` contenha uma *rota*, como `home/johndoe/myfile.txt`.

Então, a URL para este arquivo deveria ser algo como: `/files/home/johndoe/myfile.txt`.

### Suporte do OpenAPI

  "message": "Deep Learning FTW!"
}
```

## Path parameters containing paths { #path-parameters-containing-paths }

Let's say you have a *path operation* with a path `/files/{file_path}`.

But you need `file_path` itself to contain a *path*, like `home/johndoe/myfile.txt`.

So, the URL for that file would be something like: `/files/home/johndoe/myfile.txt`.

### OpenAPI support { #openapi-support }

```JSON
{
  "model_name": "alexnet",
  "message": "Deep Learning FTW!"
}
```

## Parámetros de path conteniendo paths

Imaginemos que tienes una *path operation* con un path `/files/{file_path}`.

Pero necesitas que `file_path` en sí mismo contenga un *path*, como `home/johndoe/myfile.txt`.

Entonces, la URL para ese archivo sería algo como: `/files/home/johndoe/myfile.txt`.

### Soporte de OpenAPI

클라이언트는 아래의 JSON 응답을 얻습니다:

```JSON
{
  "model_name": "alexnet",
  "message": "Deep Learning FTW!"
}
```

## 경로를 포함하는 경로 매개변수

경로를 포함하는 *경로 작동* `/files/{file_path}`이 있다고 해봅시다.

그런데 이 경우 `file_path` 자체가 `home/johndoe/myfile.txt`와 같은 경로를 포함해야 합니다.

이때 해당 파일의 URL은 다음처럼 됩니다: `/files/home/johndoe/myfile.txt`.

### OpenAPI 지원

```JSON
{
  "model_name": "alexnet",
  "message": "Deep Learning FTW!"
}
```

## Yol İçeren Yol Parametreleri

Farz edelim ki elinizde `/files/{file_path}` isminde bir *yol operasyonu* var.

Fakat `file_path` değerinin `home/johndoe/myfile.txt` gibi bir *yol* barındırmasını istiyorsunuz.

Sonuç olarak, oluşturmak istediğin URL `/files/home/johndoe/myfile.txt` gibi bir şey olacaktır.