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Results 1 - 6 of 6 for expr (0.12 sec)
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analysis/analysis-api-fir/src/org/jetbrains/kotlin/analysis/api/fir/components/KtFirReferenceShortener.kt
}?.candidate?.originScope /** * Returns whether a member of companion is used to initialize the enum entry or not. For example, * enum class C(val i: Int) { * ONE(<expr>C.K</expr>) // C.ONE uses C.K for initialization * ; * companion object { * const val K = 1 * } * } */
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analysis/analysis-api-fir/src/org/jetbrains/kotlin/analysis/api/fir/components/KtFirExpressionTypeProvider.kt
val valueArgument = unwrapQualified<KtValueArgument> { valueArg, expr -> // If `valueArg` is [KtLambdaArgument], its [getArgumentExpression] could be labeled expression (e.g., l@{ ... }). // That is not exactly `expr`, which would be [KtLambdaExpression]. So, we need [unwrap] here. valueArg.getArgumentExpression()?.unwrap() == expr } ?: return null val callExpression =
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analysis/analysis-api-fir/src/org/jetbrains/kotlin/analysis/api/fir/evaluate/FirAnnotationValueConverter.kt
var representativePsi: KtElement? = null val flattenedVarargs = buildList { for (expr in this@convertVarargsExpression) { val converted = expr.convertConstantExpression(builder) ?: continue if ((expr is FirSpreadArgumentExpression || expr is FirNamedArgumentExpression) && converted is KtArrayAnnotationValue) { addAll(converted.values)
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analysis/analysis-api-fir/src/org/jetbrains/kotlin/analysis/api/fir/components/KtFirDataFlowInfoProvider.kt
if (!PsiTreeUtil.isAncestor(defaultStatementFromFir, defaultStatement, false)) { // In certain cases, expressions might be different in PSI and FIR sources. // E.g., in 'foo.<expr>bar()</expr>', there is no FIR expression that corresponds to the 'bar()' KtCallExpression. return null } return firDefaultStatement.resolvedType }
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analysis/analysis-api-fir/src/org/jetbrains/kotlin/analysis/api/fir/components/KtFirCallResolver.kt
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.idea/dictionaries/igor.xml
<component name="ProjectDictionaryState"> <dictionary name="igor"> <words> <w>addr</w> <w>descr</w> <w>exprs</w> <w>voidification</w> <w>voidifier</w> <w>voidify</w> </words> </dictionary>
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