if (!cg_mu_) {
    return Status(absl::StatusCode::kFailedPrecondition,
                  "This QueueRunner doesn't collect a cost graph.");
  }
  mutex_lock l(*cg_mu_);
  cost_graph->MergeFrom(*cost_graph_);
  return absl::OkStatus();
}

void QueueRunner::SetRunArgumentsAndCostGraph(const RunOptions& run_options) {
  cg_mu_.reset(new mutex());
  {
    mutex_lock l(*cg_mu_);

  std::unique_ptr<BlockingCounter> counter_;

  Coordinator* coord_;

  std::atomic<bool> stopped_;

  mutex cb_mu_;
  std::vector<std::function<void(Status)>> callbacks_;

  mutable std::unique_ptr<mutex> cg_mu_;
  std::unique_ptr<CostGraphDef> cost_graph_ TF_GUARDED_BY(cg_mu_);
  RunOptions run_options_;
};

}  // namespace tensorflow

CN you write MC/NG × CG as above, then the perpendicular velocity of any other emerging Ray CE which was AD/EF × CF, will be equal to the square Root of CD_q_ + (_MCq/NGq_ × CG_q_). And by squaring these Equals, and adding to them the Equals AD_q_ and MC_q_ - CD_q_, and dividing the Sums by the Equals CF_q_ + EF_q_ and CG_q_ + NG_q_, you will have _MCq/NGq_ equal to _ADq/EFq_. Whence AD, the Sine of Incidence, is to EF the Sine of Refraction, as MC to NG, that is, in a given _ratio_. And this Demonstration...

emerging Ray CE which was AD/EF × CF, will be equal to the square Root
of CD_q_ + (_MCq/NGq_ × CG_q_). And by squaring these Equals, and adding
to them the Equals AD_q_ and MC_q_ - CD_q_, and dividing the Sums by the
Equals CF_q_ + EF_q_ and CG_q_ + NG_q_, you will have _MCq/NGq_ equal to
_ADq/EFq_. Whence AD, the Sine of Incidence, is to EF the Sine of

function subGarbageCollectionEventName(event){const topEvent=findParent(event,isTopGarbageCollectionEvent);const prefix=topEvent?topGarbageCollectionEventName(topEvent):'unknown';const name=event.title.replace('V8.GC_MC_','').replace('V8.GC_SCAVENGER_','').replace('V8.GC_','').replace(/_/g,'-').toLowerCase();return prefix+'-'+name;}