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Results 1 - 1 of 1 for bufferNoEscape5 (0.17 sec)
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test/fixedbugs/issue7921.go
useBuffer(&b) return b.Bytes() // ERROR "inlining call to bytes.\(\*Buffer\).Bytes$" } func bufferNoEscape5() { // ERROR "can inline bufferNoEscape5$" b := bytes.NewBuffer(make([]byte, 0, 128)) // ERROR "&bytes.Buffer{...} does not escape$" "make\(\[\]byte, 0, 128\) does not escape$" "inlining call to bytes.NewBuffer$" useBuffer(b) }
Registered: Wed Jun 12 16:32:35 UTC 2024 - Last Modified: Thu Sep 14 19:43:26 UTC 2023 - 2.2K bytes - Viewed (0)