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Results 1 - 1 of 1 for bufferNoEscape3 (0.11 sec)
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test/fixedbugs/issue7921.go
for _, x := range xs { b.WriteString(x) } return b.Len() // ERROR "inlining call to bytes.\(\*Buffer\).Len$" } func bufferNoEscape3(xs []string) string { // ERROR "xs does not escape$" b := bytes.NewBuffer(make([]byte, 0, 64)) // ERROR "&bytes.Buffer{...} does not escape$" "make\(\[\]byte, 0, 64\) does not escape$" "inlining call to bytes.NewBuffer$"
Registered: Wed Jun 12 16:32:35 UTC 2024 - Last Modified: Thu Sep 14 19:43:26 UTC 2023 - 2.2K bytes - Viewed (0)