align(2);
        return Short.reverseBytes(this.dis.readShort());
    }


    public int readInt () throws IOException {
        align(4);
        return Integer.reverseBytes(this.dis.readInt());
    }


    public long readLong () throws IOException {
        align(8);
        return Long.reverseBytes(this.dis.readLong());
    }

        return Long.reverseBytes(bigEndian);
      }

      @Override
      public void putLongLittleEndian(byte[] array, int offset, long value) {
        // Reverse the order of the bytes before storing, since we're on big-endian hardware.
        long littleEndianValue = Long.reverseBytes(value);

   * little-endian byte order.
   *
   * @throws IOException if an I/O error occurs
   */
  @Override
  public void writeLong(long v) throws IOException {
    ((DataOutputStream) out).writeLong(Long.reverseBytes(v));
  }

  /**
   * Writes a {@code short} as specified by {@link DataOutputStream#writeShort(int)}, except using
   * little-endian byte order.
   *
   * @throws IOException if an I/O error occurs

pkg math/bits, func Reverse16(uint16) uint16
pkg math/bits, func Reverse32(uint32) uint32
pkg math/bits, func Reverse64(uint64) uint64
pkg math/bits, func Reverse8(uint8) uint8
pkg math/bits, func ReverseBytes(uint) uint
pkg math/bits, func ReverseBytes16(uint16) uint16
pkg math/bits, func ReverseBytes32(uint32) uint32
pkg math/bits, func ReverseBytes64(uint64) uint64
pkg math/bits, func RotateLeft(uint, int) uint

  }

  public void testHashIntReverseBytesVsHashBytesIntsToByteArray() {
    int input = 42;
    assertEquals(
        Hashing.md5().hashBytes(Ints.toByteArray(input)),
        Hashing.md5().hashInt(Integer.reverseBytes(input)));
  }

  public void testHashIntVsForLoop() {
    int input = 42;
    HashCode expected = Hashing.md5().hashInt(input);

    Hasher hasher = Hashing.md5().newHasher();

 * <i>little-endian</i> order. That is, hashing the byte array {@code {0x01, 0x02, 0x03, 0x04}} is
 * equivalent to hashing the {@code int} value {@code 0x04030201}. If this isn't what you need,
 * methods such as {@link Integer#reverseBytes} and {@link Ints#toByteArray} will help.
 *
 * <h3>Relationship to {@link Object#hashCode}</h3>
 *
 * <p>Java's baked-in concept of hash codes is constrained to 32 bits, and provides no separation

 * <i>little-endian</i> order. That is, hashing the byte array {@code {0x01, 0x02, 0x03, 0x04}} is
 * equivalent to hashing the {@code int} value {@code 0x04030201}. If this isn't what you need,
 * methods such as {@link Integer#reverseBytes} and {@link Ints#toByteArray} will help.
 *
 * <h3>Relationship to {@link Object#hashCode}</h3>
 *
 * <p>Java's baked-in concept of hash codes is constrained to 32 bits, and provides no separation

    }

    // Then hash the result array
    byte[] result = hashFunction.hash(hashes, 0);

    // interpreted in little-endian order.
    int verification = Integer.reverseBytes(Ints.fromByteArray(result));

    if (expected != verification) {
      throw new AssertionError(
          "Expected: "
              + Integer.toHexString(expected)
              + " got: "