ob??irut?m!p??p?r?t??o&a!v??b!retiv??c!cel??enuc?g!ivor??i&dem&-onadipmac?onadipmac??pmet&-aiblo?aiblo??rdnos?zal??l?m!a&greb?ret??oc?re&f?lap???n!a&dipmac&-oidem?oidem??lim?tsiro?zlob??ecip&-ilocsa?ilocsa??i&bru&-orasep?orasep??lleva?rot?tnert??r&elas?ovil??ulleb??p?r!a&sep&-onibru?onibru??znatac??oun??s!ivert?sabopmac??t!arp?e&nev?ssorg??n&arat?e&girga?rt?veneb????zz&era?urba???p&a?ohsdaerpsym,s?t??qa?r&a!m?s??b!a??c?f?g?k?me?o?p?s?t?v??s&a&b?iselgi&-ainobrac?ainobrac???b?c?elpan?i?m?o&t?x&bi,...

 *   <li>Next, if only one {@code Bar} is null, that null value is treated as <i>lesser</i>
 *   <li>Finally, natural ordering is used (i.e. the result of {@code Bar.compareTo(Bar)} is
 *       returned)
 * </ol>
 *
 * <p>Alas, {@link #reverse} is a little different. As you read backwards through a chain and
 * encounter a call to {@code reverse}, continue working backwards until a result is determined, and
 * then reverse that result.
 *