corresponding receive from that channel.
</p>

<p>
This program:
</p>

<pre>
var c = make(chan int, 10)
var a string

func f() {
	a = "hello, world"
	c &lt;- 0
}

func main() {
	go f()
	&lt;-c
	print(a)
}
</pre>

<p>
is guaranteed to print <code>"hello, world"</code>.  The write to <code>a</code>

var i = 1<<s                   // 1 has type int
var j int32 = 1<<s             // 1 has type int32; j == 0
var k = uint64(1<<s)           // 1 has type uint64; k == 1<<33
var m int = 1.0<<s             // 1.0 has type int; m == 1<<33
var n = 1.0<<s == j            // 1.0 has type int32; n == true
var o = 1<<s == 2<<s           // 1 and 2 have type int; o == false

                versions[version!!] = date
            }
        }
        return versions
    }


    private
    fun String.escape() = replace("<", "&lt;").replace(">", "&gt;")
}


private
typealias Version = String


private
typealias IncubatingDescription = String


private

One is in constant evaluation.
Constant expressions in the assembler are parsed using Go's operator
precedence, not the C-like precedence of the original.
Thus <code>3&amp;1&lt;&lt;2</code> is 4, not 0—it parses as <code>(3&amp;1)&lt;&lt;2</code>
not <code>3&amp;(1&lt;&lt;2)</code>.
Also, constants are always evaluated as 64-bit unsigned integers.
Thus <code>-2</code> is not the integer value minus two,

                    }
                    writer.println("</ul>")
                }
            }
            writer.println("</body></html>")
        }
    }

    private
    fun String.escape() = replace("<", "&lt;").replace(">", "&gt;")
}

var i = 1<<s                   // 1 has type int
var j int32 = 1<<s             // 1 has type int32; j == 0
var k = uint64(1<<s)           // 1 has type uint64; k == 1<<33
var m int = 1.0<<s             // 1.0 has type int; m == 1<<33
var n = 1.0<<s == j            // 1.0 has type int32; n == true
var o = 1<<s == 2<<s           // 1 and 2 have type int; o == false