}
  }

  /**
   * Returns an immutable list containing the given elements, sorted according to their natural
   * order. The sorting algorithm used is stable, so elements that compare as equal will stay in the
   * order in which they appear in the input.
   *
   * <p>If your data has no duplicates, or you wish to deduplicate elements, use {@code

      @Override
      protected Iterator<Integer> newTargetIterator() {
        return Iterators.filter(list.iterator(), isEven);
      }
    }.test();
  }

  public void testAny() {
    List<String> list = Lists.newArrayList();
    Predicate<String> predicate = Predicates.equalTo("pants");

    assertFalse(Iterators.any(list.iterator(), predicate));
    list.add("cool");

   *
   * However, for a variety of reasons, Google developers have written a ton of code over the past
   * decade that assumes that they can use checkNotNull for non-precondition checks. I had hoped to
   * take a principled stand on this, but the amount of such code is simply overwhelming. To avoid
   * creating a lot of compile errors that users would not find to be informative, we're giving in

        return;
      }

      /*
       * Reclassify nodes in each list to new Map. Because we are using power-of-two expansion, the
       * elements from each bin must either stay at same index, or move with a power of two offset.
       * We eliminate unnecessary node creation by catching cases where old nodes can be reused

    Iterable<String> iterable = asList(sourceArray);
    String[] newArray = Iterables.toArray(iterable, String.class);
    assertTrue(Arrays.equals(sourceArray, newArray));
  }

  public void testAny() {
    List<String> list = newArrayList();
    Predicate<String> predicate = Predicates.equalTo("pants");

    assertFalse(Iterables.any(list, predicate));
    list.add("cool");

        return;
      }

      /*
       * Reclassify nodes in each list to new Map. Because we are using power-of-two expansion, the
       * elements from each bin must either stay at same index, or move with a power of two offset.
       * We eliminate unnecessary node creation by catching cases where old nodes can be reused

    Iterable<String> iterable = asList(sourceArray);
    String[] newArray = Iterables.toArray(iterable, String.class);
    assertTrue(Arrays.equals(sourceArray, newArray));
  }

  public void testAny() {
    List<String> list = newArrayList();
    Predicate<String> predicate = Predicates.equalTo("pants");

    assertFalse(Iterables.any(list, predicate));
    list.add("cool");

      @Override
      protected Iterator<Integer> newTargetIterator() {
        return Iterators.filter(list.iterator(), isEven);
      }
    }.test();
  }

  public void testAny() {
    List<String> list = Lists.newArrayList();
    Predicate<String> predicate = Predicates.equalTo("pants");

    assertFalse(Iterators.any(list.iterator(), predicate));
    list.add("cool");

   *
   * However, for a variety of reasons, Google developers have written a ton of code over the past
   * decade that assumes that they can use checkNotNull for non-precondition checks. I had hoped to
   * take a principled stand on this, but the amount of such code is simply overwhelming. To avoid
   * creating a lot of compile errors that users would not find to be informative, we're giving in

  }

  /**
   * Returns an immutable list containing the given elements, sorted according to their natural
   * order. The sorting algorithm used is stable, so elements that compare as equal will stay in the
   * order in which they appear in the input.
   *
   * <p>If your data has no duplicates, or you wish to deduplicate elements, use {@code