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Results 1 - 5 of 5 for EC (0.13 sec)

  1. docs/config/README.md

    ```
    KEY:
    storage_class  define object level redundancy
    
    ARGS:
    standard  (string)    set the parity count for default standard storage class e.g. "EC:4"
    rrs       (string)    set the parity count for reduced redundancy storage class e.g. "EC:2"
    comment   (sentence)  optionally add a comment to this setting
    ```
    
    or environment variables
    
    ```
    KEY:
    storage_class  define object level redundancy
    
    ARGS:
    Plain Text
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  2. docs/erasure/storage-class/README.md

    The default value for the `STANDARD` storage class depends on the number of volumes in the erasure set:
    
    | Erasure Set Size | Default Parity (EC:N) |
    |------------------|-----------------------|
    | 5 or fewer       |                 EC:2  |
    | 6-7              |                 EC:3  |
    | 8 or more        |                 EC:4  |
    
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  3. docs/tls/README.md

    ```sh
    openssl ecparam -genkey -name prime256v1 | openssl ec -out private.key
    ```
    
    A response similar to this one should be displayed:
    
    ```
    read EC key
    writing EC key
    ```
    
    Alternatively, use the following command to generate a private ECDSA key protected by a password:
    
    ```sh
    openssl ecparam -genkey -name prime256v1 | openssl ec -aes256 -out private.key -passout pass:PASSWORD
    ```
    
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  4. docs/erasure/README.md

    drives you provide into erasure-coding sets of *2 to 16* drives.  Therefore, the number of drives you present must be a multiple of one of these numbers.  Each object is written to a single erasure-coding set.
    
    Minio uses the largest possible EC set size which divides into the number of drives given. For example, *18 drives* are configured as *2 sets of 9 drives*, and *24 drives* are configured as *2 sets of 12 drives*.  This is true for scenarios when running MinIO as a standalone erasure...
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  5. docs/distributed/README.md

    - **MinIO chooses the largest EC set size which divides into the total number of drives or total number of nodes given - making sure to keep the uniform distribution i.e each node participates equal number of drives per set**.
    - **Each object is written to a single EC set, and therefore is spread over no more than 16 drives.**
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