}

  /**
   * Wrapper for {@link Map#get(Object)} that forces the caller to pass in a key of the same type as
   * the map. Besides being slightly shorter than code that uses {@link #getMap()}, it also ensures
   * that callers don't pass an {@link Entry} by mistake.
   */
  protected V get(K key) {
    return getMap().get(key);
  }

  protected final K k0() {

  }

  /**
   * Wrapper for {@link Map#get(Object)} that forces the caller to pass in a key of the same type as
   * the map. Besides being slightly shorter than code that uses {@link #getMap()}, it also ensures
   * that callers don't pass an {@link Entry} by mistake.
   */
  protected V get(K key) {
    return getMap().get(key);
  }

  protected final K k0() {

   * compares, using {@link #compare(int, int)}), the first pair of values that follow any common
   * prefix, or when one array is a prefix of the other, treats the shorter array as the lesser. For
   * example, {@code [] < [1] < [1, 2] < [2] < [1 << 31]}.
   *
   * <p>The returned comparator is inconsistent with {@link Object#equals(Object)} (since arrays

   * compares, using {@link #compare(int, int)}), the first pair of values that follow any common
   * prefix, or when one array is a prefix of the other, treats the shorter array as the lesser. For
   * example, {@code [] < [1] < [1, 2] < [2] < [1 << 31]}.
   *
   * <p>The returned comparator is inconsistent with {@link Object#equals(Object)} (since arrays

   *   (arg1, arg2) -> arg1 + ":" + arg2)
   * }</pre>
   *
   * <p>will return {@code Stream.of("foo1:bar1", "foo2:bar2")}.
   *
   * <p>The resulting stream will only be as long as the shorter of the two input streams; if one
   * stream is longer, its extra elements will be ignored.
   *
   * <p>Note that if you are calling {@link Stream#forEach} on the resulting stream, you might want

   * Returns a new ordering which sorts iterables by comparing corresponding elements pairwise until
   * a nonzero result is found; imposes "dictionary order". If the end of one iterable is reached,
   * but not the other, the shorter iterable is considered to be less than the longer one. For
   * example, a lexicographical natural ordering over integers considers {@code [] < [1] < [1, 1] <
   * [1, 2] < [2]}.
   *

   * Returns a new ordering which sorts iterables by comparing corresponding elements pairwise until
   * a nonzero result is found; imposes "dictionary order". If the end of one iterable is reached,
   * but not the other, the shorter iterable is considered to be less than the longer one. For
   * example, a lexicographical natural ordering over integers considers {@code [] < [1] < [1, 1] <
   * [1, 2] < [2]}.
   *

   *   (arg1, arg2) -> arg1 + ":" + arg2)
   * }</pre>
   *
   * <p>will return {@code Stream.of("foo1:bar1", "foo2:bar2")}.
   *
   * <p>The resulting stream will only be as long as the shorter of the two input streams; if one
   * stream is longer, its extra elements will be ignored.
   *
   * <p>Note that if you are calling {@link Stream#forEach} on the resulting stream, you might want

  /**
   * Returns a builder that creates immutable sorted maps whose keys are ordered by their natural
   * ordering. The sorted maps use {@link Ordering#natural()} as the comparator.
   */
  public static <K extends Comparable<?>, V> Builder<K, V> naturalOrder() {
    return new Builder<>(Ordering.natural());
  }

  /**
   * Returns a builder that creates immutable sorted maps with an explicit comparator. If the

      Comparator<? super E> comparator, Collection<? extends E> elements) {
    return copyOf(comparator, (Iterable<? extends E>) elements);
  }

  /**
   * Returns an immutable sorted set containing the elements of a sorted set, sorted by the same
   * {@code Comparator}. That behavior differs from {@link #copyOf(Iterable)}, which always uses the
   * natural ordering of the elements.
   *