for (double fpp = Double.MIN_VALUE; fpp < 1.0; fpp += 0.001) {
        assertThat(BloomFilter.optimalNumOfBits(n, fpp)).isAtLeast(0);
      }
    }

    // some random values
    Random random = new Random(0);
    for (int repeats = 0; repeats < 10000; repeats++) {
      assertThat(BloomFilter.optimalNumOfBits(random.nextInt(1 << 16), random.nextDouble()))
          .isAtLeast(0);
    }

     * is proportional to -log(p), but there is not much of a point after all, e.g.
     * optimalM(1000, 0.0000000000000001) = 76680 which is less than 10kb. Who cares!
     */
    long numBits = optimalNumOfBits(expectedInsertions, fpp);
    int numHashFunctions = optimalNumOfHashFunctions(fpp);
    try {
      return new BloomFilter<>(new LockFreeBitArray(numBits), numHashFunctions, funnel, strategy);