* </ul>
 *
 * <p>The class uses case-insensitive pattern matching for user agents and supports
 * wildcard characters (*) in user agent strings. When multiple directives match a user agent,
 * the most specific (longest) match is used.</p>
 *
 */
public class RobotsTxt {
    private static final String ALL_BOTS = "*";

    /** Map of user agent patterns to their corresponding directives. */

    for (policy in addressStates.values) {
      policy.scheduleOpener()
    }
  }

  /**
   * Performs maintenance on this pool, evicting the connection that has been idle the longest if
   * either it has exceeded the keep alive limit or the idle connections limit.
   *
   * Returns the duration in nanoseconds to sleep until the next scheduled call to this method.

    for (n = len; n < size - n; n <<= 1) {
      System.arraycopy(array, 0, array, n, n);
    }
    System.arraycopy(array, 0, array, n, size - n);
    return new String(array);
  }

  /**
   * Returns the longest string {@code prefix} such that {@code a.toString().startsWith(prefix) &&
   * b.toString().startsWith(prefix)}, taking care not to split surrogate pairs. If {@code a} and
   * {@code b} have no common prefix, returns the empty string.

    // Start by looking for exact matches. We start at the leftmost label. For example, foo.bar.com
    // will look like: [foo, bar, com], [bar, com], [com]. The longest matching rule wins.
    var exactMatch: String? = null
    for (i in domainLabelsUtf8Bytes.indices) {
      val rule = publicSuffixList.bytes.binarySearch(domainLabelsUtf8Bytes, i)
      if (rule != null) {

                    }
                }
            }
        }

        if (dr == null && path != null) {
            /* We did not match a domain based root. Now try to match the
             * longest path in the list of stand-alone referrals.
             */
            if (referrals != null && now > referrals.expiration) {
                referrals = null;
            }
            if (referrals == null) {

/**
 * A bounded {@linkplain BlockingQueue blocking queue} backed by an array. This queue orders
 * elements FIFO (first-in-first-out). The head of the queue is that element that has been
 * on the queue the longest time. The tail of the queue is that element that has been on
 * the queue the shortest time. New elements are inserted at the tail of the queue, and the queue
 * retrieval operations obtain elements at the head of the queue.

            log.trace("No match for domain based root, checking standalone " + domain);
        }
        /*
         * We did not match a domain based root. Now try to match the
         * longest path in the list of stand-alone referrals.
         */

        CacheEntry<DfsReferralDataInternal> refs;
        synchronized (this.referralsLock) {
            refs = this.referrals;

func restQueries(keys ...string) []string {
	var accumulator []string
	for _, key := range keys {
		accumulator = append(accumulator, key, "{"+key+":.*}")
	}
	return accumulator
}

// Suffix returns the longest common suffix of the provided strings
func lcpSuffix(strs []string) string {
	return lcp(strs, false)
}

func lcp(strs []string, pre bool) string {
	// short-circuit empty list
	if len(strs) == 0 {

			v2, ok := sm.Metrics[dID]
			if !ok {
				v2 = madmin.SRMetric{}
				v2.Failed.ErrCounts = make(map[string]int)
			}

			// use target endpoint metrics from node which has been up the longest
			if v2.LastOnline.After(v.LastOnline) || v2.LastOnline.IsZero() {
				v2.Endpoint = v.Endpoint
				v2.LastOnline = v.LastOnline
				v2.Latency = v.Latency
				v2.Online = v.Online

that would otherwise combine into a single token. Also, a newline or end of file
may trigger the insertion of a <a href="#Semicolons">semicolon</a>.
While breaking the input into tokens,
the next token is the longest sequence of characters that form a
valid token.
</p>

<h3 id="Semicolons">Semicolons</h3>

<p>
The formal syntax uses semicolons <code>";"</code> as terminators in