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Results 1 - 6 of 6 for log1p (0.03 seconds)
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android/guava/src/com/google/common/hash/BloomFilter.java
* is close to 1 (why?), gives the following formula. */ double fractionOfBitsSet = (double) bitCount / bitSize; return DoubleMath.roundToLong( -Math.log1p(-fractionOfBitsSet) * bitSize / numHashFunctions, RoundingMode.HALF_UP); } /** Returns the number of bits in the underlying bit array. */ @VisibleForTesting long bitSize() { return bits.bitSize();Created: Fri Apr 03 12:43:13 GMT 2026 - Last Modified: Tue Mar 10 22:28:12 GMT 2026 - 27.6K bytes - Click Count (0) -
guava-tests/test/com/google/common/math/BigIntegerMathTest.java
@GwtIncompatible // TODO public void testLog10HalfEven() { for (BigInteger x : POSITIVE_BIGINTEGER_CANDIDATES) { int halfEven = BigIntegerMath.log10(x, HALF_EVEN); // Now figure out what rounding mode we should behave like (it depends if FLOOR was // odd/even). boolean floorWasEven = (BigIntegerMath.log10(x, FLOOR) & 1) == 0;
Created: Fri Apr 03 12:43:13 GMT 2026 - Last Modified: Tue Mar 03 04:51:56 GMT 2026 - 27.1K bytes - Click Count (0) -
guava-tests/test/com/google/common/math/LongMathTest.java
@GwtIncompatible // TODO public void testLog10MatchesBigInteger() { for (long x : POSITIVE_LONG_CANDIDATES) { for (RoundingMode mode : ALL_SAFE_ROUNDING_MODES) { assertEquals(BigIntegerMath.log10(valueOf(x), mode), LongMath.log10(x, mode)); } } } // Relies on the correctness of log10(long, FLOOR) and of pow(long, int). @GwtIncompatible // TODO
Created: Fri Apr 03 12:43:13 GMT 2026 - Last Modified: Thu Oct 30 14:15:36 GMT 2025 - 31.4K bytes - Click Count (0) -
android/guava/src/com/google/common/math/IntMath.java
* can narrow the possible floor(log10(x)) values to two. For example, if floor(log2(x)) is 6, * then 64 <= x < 128, so floor(log10(x)) is either 1 or 2. */ int y = maxLog10ForLeadingZeros[Integer.numberOfLeadingZeros(x)]; /* * y is the higher of the two possible values of floor(log10(x)). If x < 10^y, then we want the
Created: Fri Apr 03 12:43:13 GMT 2026 - Last Modified: Thu Jan 29 22:14:05 GMT 2026 - 26.1K bytes - Click Count (0) -
android/guava/src/com/google/common/math/LongMath.java
* can narrow the possible floor(log10(x)) values to two. For example, if floor(log2(x)) is 6, * then 64 <= x < 128, so floor(log10(x)) is either 1 or 2. */ int y = maxLog10ForLeadingZeros[Long.numberOfLeadingZeros(x)]; /* * y is the higher of the two possible values of floor(log10(x)). If x < 10^y, then we want the
Created: Fri Apr 03 12:43:13 GMT 2026 - Last Modified: Mon Mar 09 23:01:02 GMT 2026 - 46.8K bytes - Click Count (0) -
RELEASE.md
`tf.math.greater`, `tf.math.greater_equal`, `tf.math.igamma`, `tf.math.igammac`, `tf.math.invert_permutation`, `tf.math.less`, `tf.math.less_equal`, `tf.math.lgamma`, `tf.math.log`, `tf.math.log1p`, `tf.math.logical_and`, `tf.math.logical_not`, `tf.math.logical_or`, `tf.math.maximum`, `tf.math.minimum`, `tf.math.not_equal`, `tf.math.polygamma`, `tf.math.reciprocal`, `tf.math.rint`,Created: Tue Apr 07 12:39:13 GMT 2026 - Last Modified: Mon Mar 30 18:31:38 GMT 2026 - 746.5K bytes - Click Count (3)