throw new NumberFormatException();
    }
    int octet = 0;
    for (int i = start; i < end; i++) {
      octet *= 10;
      int digit = Character.digit(ipString.charAt(i), 10);
      if (digit < 0) {
        throw new NumberFormatException();
      }
      octet += digit;
    }
    if (octet > 255) {
      throw new NumberFormatException();
    }
    return (byte) octet;
  }

      throw new NumberFormatException();
    }
    int octet = 0;
    for (int i = start; i < end; i++) {
      octet *= 10;
      int digit = Character.digit(ipString.charAt(i), 10);
      if (digit < 0) {
        throw new NumberFormatException();
      }
      octet += digit;
    }
    if (octet > 255) {
      throw new NumberFormatException();
    }
    return (byte) octet;
  }

            """
        ),
    ] = _Unset,
    max_digits: Annotated[
        Union[int, None],
        Doc(
            """
            Maximum number of allow digits for strings.
            """
        ),
    ] = _Unset,
    decimal_places: Annotated[
        Union[int, None],
        Doc(
            """

      for (int i = n1 + 1; i <= n2; i++) {
        result *= i;
      }
      return BigInteger.valueOf(result);
    }

    /*
     * We want each multiplication to have both sides with approximately the same number of digits.
     * Currently, we just divide the range in half.
     */
    int mid = (n1 + n2) >>> 1;
    return oldSlowFactorial(n1, mid).multiply(oldSlowFactorial(mid, n2));
  }

  @Benchmark

///

## About HTTP status codes

/// note

If you already know what HTTP status codes are, skip to the next section.

///

In HTTP, you send a numeric status code of 3 digits as part of the response.

These status codes have a name associated to recognize them, but the important part is the number.

In short:

   *
   * <p>Unlike {@link Integer#parseInt(String)}, this method returns {@code null} instead of
   * throwing an exception if parsing fails. Additionally, this method only accepts ASCII digits,
   * and returns {@code null} if non-ASCII digits are present in the string.
   *
   * <p>Note that strings prefixed with ASCII {@code '+'} are rejected, even though {@link
   * Integer#parseInt(String)} accepts them.
   *

	var (
		c       = d.cur()
		n       float64
		isFloat bool
	)

	// digits first
	switch {
	case c == '0':
		d.scratch.add(c)
		c = d.next()
	case '1' <= c && c <= '9':
		for ; c >= '0' && c <= '9'; c = d.next() {
			n = 10*n + float64(c-'0')
			d.scratch.add(c)
		}
	}

	// . followed by 1 or more digits
	if c == '.' {
		isFloat = true
		d.scratch.add(c)

            return null;
        }
        return tryParseInt(s);
    }

    private static Integer tryParseInt(String s) {
        // for performance, check digits instead of relying later on catching NumberFormatException
        if (!isDigits(s)) {
            return null;
        }

        try {
            long longValue = Long.parseLong(s);
            if (longValue > Integer.MAX_VALUE) {

      for (int i = n1 + 1; i <= n2; i++) {
        result *= i;
      }
      return BigInteger.valueOf(result);
    }

    /*
     * We want each multiplication to have both sides with approximately the same number of digits.
     * Currently, we just divide the range in half.
     */
    int mid = (n1 + n2) >>> 1;
    return oldSlowFactorial(n1, mid).multiply(oldSlowFactorial(mid, n2));
  }

  @Benchmark

	// This matches most other JSON generators.
	// See golang.org/issue/6384 and golang.org/issue/14135.
	// Like fmt %g, but the exponent cutoffs are different
	// and exponents themselves are not padded to two digits.
	abs := math.Abs(f)
	fmt := byte('f')
	if abs != 0 {
		if abs < 1e-6 || abs >= 1e21 {
			fmt = 'e'
		}
	}
	dst = strconv.AppendFloat(dst, f, fmt, -1, 64)
	if fmt == 'e' {