switch op {
	case opLt:
		return left < right
	case opLte:
		return left <= right
	case opGt:
		return left > right
	case opGte:
		return left >= right
	case opEq:
		return left == right
	case opIneq:
		return left != right
	}
	// This case does not happen
	return false
}

func boolCompare(op string, left, right bool) (bool, error) {
	switch op {
	case opEq:

<code>R0&lt;&lt;16</code>
<br>
<code>R0@&gt;16</code>:
For <code>&lt;&lt;</code>, left shift <code>R0</code> by 16 bits.
The other codes are <code>-&gt;</code> (arithmetic right shift),
<code>&gt;&gt;</code> (logical right shift), and
<code>@&gt;</code> (rotate right).
</li>

<li>
<code>R0-&gt;R1</code>
<br>
<code>R0&gt;&gt;R1</code>
<br>
<code>R0&lt;&lt;R1</code>
<br>
<code>R0@&gt;R1</code>:

					symmetry = uint64(len(p.Seq))%ss == 0
				} else {
					symmetry = ss%uint64(len(p.Seq)) == 0
				}
			}
		}
		// With no arg patterns, it is expected that user knows
		// the right symmetry, so either ellipses patterns are
		// provided (recommended) or no ellipses patterns.
		if _, ok := newSetCounts[ss]; !ok && (symmetry || argPatterns == nil) {
			newSetCounts[ss] = struct{}{}
		}
	}

        )
    }.reduce { acc, next ->
        acc.zip(next) { left, right ->
            when {
                left.isPresent -> {
                    require(!right.isPresent) {
                        "Expected at most one provider to be present"
                    }
                    left
                }
                else -> right
            }
        }
    }.map { it.orElse(null) }

func (e *Operand) analyze(s *Select) (result qProp) {
	result.combine(e.Left.analyze(s))
	for _, r := range e.Right {
		result.combine(r.Right.analyze(s))
	}
	return result
}

func (e *MultOp) analyze(s *Select) (result qProp) {
	result.combine(e.Left.analyze(s))
	for _, r := range e.Right {
		result.combine(r.Right.analyze(s))
	}
	return result
}

func (e *UnaryTerm) analyze(s *Select) (result qProp) {

            })
        }
        .reduce { acc, next ->
            acc.zip(next) { left, right ->
                when {
                    !left.isPresent -> right
                    !right.isPresent -> left
                    else -> Optional.of(combiner(left.get(), right.get()))
                }
            }
        }
        .map { it.orElse(null) }

EOF

  license_query "attr('licenses', 'notice', deps($BUILD_TARGET))" > $BATS_TEST_TMPDIR/expected_licenses
  license_query "deps($LICENSES_TARGET)" > $BATS_TEST_TMPDIR/actual_licenses

  # Column 1 is left only, Column 2 is right only, Column 3 is shared lines
  # Select lines unique to actual_licenses, i.e. extra licenses.

				"us-west-1",
				"s3",
				"ABCD"),
			expectedCredentials: credentialHeader{},
			expectedErrCode:     ErrInvalidRequestVersion,
		},
		// Test Case - 9.
		// Test case with right inputs. Expected to return a valid CredentialHeader.
		// "aws4_request" is the valid request version.
		{
			inputCredentialStr: generateCredentialStr(
				"Z7IXGOO6BZ0REAN1Q26I",
				sampleTimeStr,
				"us-west-1",

		if err != nil {
			// Read's failed for object with right size, file is corrupt.
			return err
		}
		// Subtract hash length..
		left -= int64(n)
		if left < shardSize {
			shardSize = left
		}

		read, err := io.CopyBuffer(h, io.LimitReader(r, shardSize), *bufp)
		if err != nil {
			// Read's failed for object with right size, at different offsets.
			return errFileCorrupt
		}

of expressions on the right, each of which must be single-valued, and the
<i>n</i>th expression on the right is assigned to the <i>n</i>th
operand on the left:
</p>

<pre>
one, two, three = '一', '二', '三'
</pre>

<p>
The <a href="#Blank_identifier">blank identifier</a> provides a way to
ignore right-hand side values in an assignment:
</p>

<pre>