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Results 1 - 1 of 1 for PushFront (0.04 seconds)

  1. internal/lru/lru.go

    		return
    	}
    	e.prev.next = e.next
    	e.next.prev = e.prev
    
    	e.prev = at
    	e.next = at.next
    	e.prev.next = e
    	e.next.prev = e
    }
    
    // PushFront inserts a new element e with value v at the front of list l and returns e.
    func (l *LruList[K, V]) PushFront(k K, v V) *Entry[K, V] {
    	l.lazyInit()
    	return l.insertValue(k, v, time.Time{}, &l.root)
    }
    
    Created: Sun Apr 05 09:35:12 GMT 2026
    - Last Modified: Sat Mar 21 11:35:55 GMT 2026
    - 12.6K bytes
    - Click Count (0)
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