private final E element1;
        private final E element2;

        private List2(E element1, E element2) {
            this.element1 = element1;
            this.element2 = element2;
        }

        @Override
        public E get(int index) {
            if (index == 0) {
                return element1;
            } else if (index == 1) {

        private final E element1;
        private final E element2;

        private List2(E element1, E element2) {
            this.element1 = element1;
            this.element2 = element2;
        }

        @Override
        public E get(int index) {
            if (index == 0) {
                return element1;
            } else if (index == 1) {

     *
     * @param elements the elements to add
     * @return this {@code Builder} object
     * @throws NullPointerException if {@code elements} is null or contains a null element
     */
    @CanIgnoreReturnValue
    @Override
    public Builder<E> add(E... elements) {
      super.add(elements);
      return this;
    }

    /**

     *
     * @param elements the elements to add
     * @return this {@code Builder} object
     * @throws NullPointerException if {@code elements} is null or contains a null element
     */
    @CanIgnoreReturnValue
    @Override
    public Builder<E> add(E... elements) {
      super.add(elements);
      return this;
    }

    /**

      contents.put(element, occurrences + contents.get(element));
      return this;
    }

    /**
     * Adds or removes the necessary occurrences of an element such that the element attains the
     * desired count.
     *
     * @param element the element to add or remove occurrences of
     * @param count the desired count of the element in this multiset
     * @return this {@code Builder} object

        others.length <= Integer.MAX_VALUE - 6, "the total number of elements must fit in an int");
    final int paramCount = 6;
    Object[] elements = new Object[paramCount + others.length];
    elements[0] = e1;
    elements[1] = e2;
    elements[2] = e3;
    elements[3] = e4;
    elements[4] = e5;
    elements[5] = e6;
    System.arraycopy(others, 0, elements, paramCount, others.length);

    // We special-case for 0 or 1 elements, but going further is madness.
    if (!elements.hasNext()) {
      return of();
    }
    E first = elements.next();
    if (!elements.hasNext()) {
      return of(first);
    } else {
      return new ImmutableList.Builder<E>().add(first).addAll(elements).build();
    }
  }

  /**
   * Returns an immutable list containing the given elements, in order.

   * have been removed.
   *
   * <p><b>Warning:</b> Typical uses of the resulting iterator may produce an infinite loop. You
   * should use an explicit {@code break} or be certain that you will eventually remove all the
   * elements.
   *
   * <p>To cycle over the elements {@code n} times, use the following: {@code
   * Iterables.concat(Collections.nCopies(n, Arrays.asList(elements)))}
   *

     */
    @CanIgnoreReturnValue
    @Override
    public Builder<E> add(E element) {
      return addCopies(element, 1);
    }

    /**
     * Adds each element of {@code elements} to the {@code ImmutableSortedMultiset}.
     *
     * @param elements the elements to add
     * @return this {@code Builder} object

    public Builder<E> add(E... elements) {
      for (E element : elements) {
        add(element);
      }
      return this;
    }

    /**
     * Adds each element of {@code elements} to the {@code ImmutableCollection} being built.
     *
     * <p>Note that each builder class overrides this method in order to covariantly return its own
     * type.
     *
     * @param elements the elements to add