},
        "czech_keywords": {
          "type":       "keyword_marker",
          "keywords": ["Haló", "svět", "vyhledávání"]
        },
        "czech_stemmer": {
          "type":       "stemmer",
          "language":   "czech"
        },
        "czech_override": {

        if (hiLo < 0) {
          hiLo = UnsignedLongs.remainder(hiLo, m);
        }
        // hiLo < 2^63
        result += hiLo; // result < 2^64
        result = times2ToThe32Mod(result, m); // result < m < 2^63
        return plusMod(result, UnsignedLongs.remainder(aLo * aLo /* < 2^64 */, m), m);
      }
    };

    static boolean test(long base, long n) {

labels.suggestWord=Sugerowane słowo
labels.targetLabel=Etykieta
labels.term=Termin wyszukiwania
labels.fields=Pola
labels.ex_q=Rozszerzone zapytanie
labels.oldPassword=Bieżące hasło
labels.newPassword=Nowe hasło
labels.confirmNewPassword=Potwierdź nowe hasło

labels.menu_system=System
labels.menu_wizard=Kreator
labels.menu_crawl_config=Ogólne
labels.menu_scheduler_config=Harmonogram
labels.menu_dashboard_config=Panel

# e.g.
# errors.xxx = ...
# info.xxx = ...
# _/_/_/_/_/_/_/_/_/_/
# ========================================================================================
# Fess
# ======
errors.login_error = Nazwa użytkownika lub hasło są nieprawidłowe.
errors.sso_login_error=Błąd w procesie logowania SSO.
errors.could_not_find_log_file = Nie można znaleźć {0}.
errors.failed_to_start_crawl_process = Nie można uruchomić procesu indeksowania.

szemben
szerint
szinte
talán
tehát
teljes
tovább
továbbá
több
úgy
ugyanis
új
újabb
újra
után
utána
utolsó
vagy
vagyis
valaki
valami
valamint
való
vagyok
van
vannak
volt
voltam
voltak
voltunk
vissza
vele
viszont

  private final long k1;

  /**
   * @param c the number of compression rounds (must be positive)
   * @param d the number of finalization rounds (must be positive)
   * @param k0 the first half of the key
   * @param k1 the second half of the key
   */
  SipHashFunction(int c, int d, long k0, long k1) {
    checkArgument(
        c > 0, "The number of SipRound iterations (c=%s) during Compression must be positive.", c);

  static <R, C, V> RegularImmutableTable<R, C, V> forOrderedComponents(
      ImmutableList<Cell<R, C, V>> cellList,
      ImmutableSet<R> rowSpace,
      ImmutableSet<C> columnSpace) {
    // use a dense table if more than half of the cells have values
    // TODO(gak): tune this condition based on empirical evidence
    return (cellList.size() > (((long) rowSpace.size() * columnSpace.size()) / 2))

      }
      return BigInteger.valueOf(result);
    }

    /*
     * We want each multiplication to have both sides with approximately the same number of digits.
     * Currently, we just divide the range in half.
     */
    int mid = (n1 + n2) >>> 1;
    return oldSlowFactorial(n1, mid).multiply(oldSlowFactorial(mid, n2));
  }

  @Benchmark
  int slowFactorial(int reps) {
    int tmp = 0;

      return entry.value;
    }
    entry = cacheEntry2;
    if (entry != null && entry.key == key) {
      // Promote second cache entry to first so the access pattern
      // [K1, K2, K1, K3, K1, K4...] still hits the cache half the time.
      addToCache(entry);
      return entry.value;
    }
    return null;
  }

  @Override
  void clearCache() {
    super.clearCache();
    cacheEntry1 = null;
    cacheEntry2 = null;
  }

  }

  private static long random() {
    return randomSource.nextLong();
  }

  // A random value that cannot be 0 and that is unsigned-less-than or equal
  // to the given dividend, so that we don't have half of our divisions being
  // trivial because the divisor is bigger than the dividend.
  // Using remainder here does not give us a uniform distribution but it should
  // not have a big impact on the measurement.