});
  
  clipboard = new ClipboardJS(".url-copy");
  clipboard.on("success", function(e) {
    e.trigger.classList.remove("url-copy");
    e.trigger.classList.remove("far");
    e.trigger.classList.remove("fa-copy");
    e.trigger.classList.add("url-copied");
    e.trigger.classList.add("fas");
    e.trigger.classList.add("fa-check");
    setTimeout(function(){

						>
						</a>
					</div>
					</c:if>
					<div class="description">${doc.content_description}</div>
				</div>
				<div class="site text-truncate">
					<c:if test="${clipboardCopyIcon}"><i class="far fa-copy url-copy d-print-none" data-clipboard-text="${doc.url_link}"></i></c:if>
					<cite>${f:h(doc.site_path)}</cite>
				</div>
				<div class="more">
					<a href="#result${s.index}"><la:message

    // To start, fill up the cache.
    // Each miss both increments the counter and causes the map to grow by one,
    // so until evictions begin, the size of the map is the greatest return
    // value seen so far
    while (cache.getUnchecked(nextRandomKey()) < maximumSize) {}

    requests.set(0);
    misses.set(0);
  }

  @Benchmark
  int time(int reps) {
    int dummy = 0;
    for (int i = 0; i < reps; i++) {

      }
    }
  }

  private static String oldRepeat(String string, int count) {
    // If this multiplication overflows, a NegativeArraySizeException or
    // OutOfMemoryError is not far behind
    int len = string.length();
    int size = len * count;
    char[] array = new char[size];
    for (int i = 0; i < size; i += len) {
      string.getChars(0, len, array, i);
    }
    return new String(array);

						>
						</a>
					</div>
					</c:if>
					<div class="description">${doc.content_description}</div>
				</div>
				<div class="site text-truncate">
					<c:if test="${clipboardCopyIcon}"><i class="far fa-copy url-copy d-print-none" data-clipboard-text="${doc.url_link}"></i></c:if>
					<cite>${f:h(doc.site_path)}</cite>
				</div>
				<div class="more">
					<a href="#result${s.index}"><la:message

      }
      dummy ^= sb.toString().length();
    }
    return dummy;
  }

  /**
   * Similar to the above, but keeps a boolean flag rather than checking for the string accumulated
   * so far being empty. As a result, it does not have the above-mentioned bug.
   */
  @Benchmark
  int booleanIfFirst(int reps) {
    int dummy = 0;
    for (int i = 0; i < reps; i++) {

   * mode}.
   *
   * <p>For the case of {@link RoundingMode#HALF_DOWN}, {@code HALF_UP}, and {@code HALF_EVEN},
   * infinite {@code double} values are considered infinitely far away. For example, 2^2000 is not
   * representable as a double, but {@code roundToDouble(BigDecimal.valueOf(2).pow(2000), HALF_UP)}
   * will return {@code Double.MAX_VALUE}, not {@code Double.POSITIVE_INFINITY}.
   *

      }
    }
  }

  private static String oldRepeat(String string, int count) {
    // If this multiplication overflows, a NegativeArraySizeException or
    // OutOfMemoryError is not far behind
    int len = string.length();
    int size = len * count;
    char[] array = new char[size];
    for (int i = 0; i < size; i += len) {
      string.getChars(0, len, array, i);
    }
    return new String(array);

    // To start, fill up the cache.
    // Each miss both increments the counter and causes the map to grow by one,
    // so until evictions begin, the size of the map is the greatest return
    // value seen so far
    while (cache.getUnchecked(nextRandomKey()) < maximumSize) {}

    requests.set(0);
    misses.set(0);
  }

  @Benchmark
  int time(int reps) {
    int dummy = 0;
    for (int i = 0; i < reps; i++) {

   * mode}.
   *
   * <p>For the case of {@link RoundingMode#HALF_DOWN}, {@code HALF_UP}, and {@code HALF_EVEN},
   * infinite {@code double} values are considered infinitely far away. For example, 2^2000 is not
   * representable as a double, but {@code roundToDouble(BigDecimal.valueOf(2).pow(2000), HALF_UP)}
   * will return {@code Double.MAX_VALUE}, not {@code Double.POSITIVE_INFINITY}.
   *