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Results 1 - 1 of 1 for PushFront (0.33 sec)
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internal/lru/lru.go
return } e.prev.next = e.next e.next.prev = e.prev e.prev = at e.next = at.next e.prev.next = e e.next.prev = e } // PushFront inserts a new element e with value v at the front of list l and returns e. func (l *LruList[K, V]) PushFront(k K, v V) *Entry[K, V] { l.lazyInit() return l.insertValue(k, v, time.Time{}, &l.root) }
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