if container.Name != "istio-proxy" && container.Name != "istio-operator" {
			if container.SecurityContext != nil && container.SecurityContext.RunAsUser != nil {
				if *container.SecurityContext.RunAsUser == UserID {
					fmt.Fprintf(writer, "WARNING: User ID (UID) 1337 is reserved for the sidecar proxy.\n")
				}
			}
		}
	}

	fmt.Fprintf(writer, "Pod: %s\n", kname(pod.ObjectMeta))
	fmt.Fprintf(writer, "   Pod Revision: %s\n", revision)

As in the example above we got `user_dict` from `user_in.dict()`, this code:

```Python
user_dict = user_in.dict()
UserInDB(**user_dict)
```

would be equivalent to:

```Python
UserInDB(**user_in.dict())
```

...because `user_in.dict()` is a `dict`, and then we make Python "unwrap" it by passing it to `UserInDB` prefixed with `**`.

```

////

### 🔃 `**user_in.dict()`

#### Pydantic `.dict()`

`user_in` Pydantic 🏷 🎓 `UserIn`.

Pydantic 🏷 ✔️ `.dict()` 👩‍🔬 👈 📨 `dict` ⏮️ 🏷 💽.

, 🚥 👥 ✍ Pydantic 🎚 `user_in` 💖:

```Python
user_in = UserIn(username="john", password="secret", email="******@****.***")
```

& ⤴️ 👥 🤙:

```Python
user_dict = user_in.dict()
```

{!> ../../docs_src/extra_models/tutorial001.py!}
```

////

### Про `**user_in.dict()`

#### `.dict()` из Pydantic

`user_in` - это Pydantic-модель класса `UserIn`.

У Pydantic-моделей есть метод `.dict()`, который возвращает `dict` с данными модели.

Поэтому, если мы создадим Pydantic-объект `user_in` таким способом:

```Python
user_in = UserIn(username="john", password="secret", email="******@****.***")
```

Como no exemplo acima, obtivemos o `user_dict` a partir do `user_in.dict()`, este código:

```Python
user_dict = user_in.dict()
UserInDB(**user_dict)
```

seria equivalente a:

```Python
UserInDB(**user_in.dict())
```

...porque `user_in.dict()` é um `dict`, e depois fazemos o Python "desembrulhá-lo" passando-o para UserInDB precedido por `**`.

Da wir in obigem Beispiel `user_dict` mittels `user_in.dict()` erzeugt haben, ist dieser Code:

```Python
user_dict = user_in.dict()
UserInDB(**user_dict)
```

äquivalent zu:

```Python
UserInDB(**user_in.dict())
```

... weil `user_in.dict()` ein `dict` ist, und dann lassen wir Python es „entpacken“, indem wir es `UserInDB` übergeben, mit vorangestelltem `**`.

)
```

#### 用其它模型中的内容生成 Pydantic 模型

上例中 ，从 `user_in.dict()` 中得到了 `user_dict`，下面的代码：

```Python
user_dict = user_in.dict()
UserInDB(**user_dict)
```

等效于：

```Python
UserInDB(**user_in.dict())
```

……因为 `user_in.dict()` 是字典，在传递给 `UserInDB` 时，把 `**` 加在  `user_in.dict()` 前，可以让 Python 进行**解包**。

这样，就可以用其它 Pydantic 模型中的数据生成 Pydantic 模型。

      SQLCMDPASSWORD=LoremIpsum86 sqlcmd -U sa -S localhost:9930 -Q "IF SUSER_ID (N'gorm') IS NULL CREATE LOGIN gorm WITH PASSWORD = 'LoremIpsum86';" > /dev/null || true
      SQLCMDPASSWORD=LoremIpsum86 sqlcmd -U sa -S localhost:9930 -Q "IF USER_ID (N'gorm') IS NULL CREATE USER gorm FROM LOGIN gorm; ALTER SERVER ROLE sysadmin ADD MEMBER [gorm];" > /dev/null || true
    else

{!../../docs_src/extra_models/tutorial001.py!}
```

### `**user_in.dict()`について

#### Pydanticの`.dict()`

`user_in`は`UserIn`クラスのPydanticモデルです。

Pydanticモデルには、モデルのデータを含む`dict`を返す`.dict()`メソッドがあります。

そこで、以下のようなPydanticオブジェクト`user_in`を作成すると:

```Python
user_in = UserIn(username="john", password="secret", email="******@****.***")
```

そして呼び出すと:

```Python
user_dict = user_in.dict()
```

`BaseUser` has the base fields. Then `UserIn` inherits from `BaseUser` and adds the `password` field, so, it will include all the fields from both models.

We annotate the function return type as `BaseUser`, but we are actually returning a `UserIn` instance.