Então nós podemos utilizar o `secrets.compare_digest()` para garantir que o `credentials.username` é `"stanleyjobson"`, e que o `credentials.password` é `"swordfish"`.

//// tab | Python 3.9+

```Python hl_lines="1  12-24"
{!> ../../docs_src/security/tutorial007_an_py39.py!}
```

////

//// tab | Python 3.8+

```Python hl_lines="1  12-24"

⤴️ 👥 💪 ⚙️ `secrets.compare_digest()` 🚚 👈 `credentials.username` `"stanleyjobson"`, & 👈 `credentials.password` `"swordfish"`.

```Python hl_lines="1  11-21"
{!../../docs_src/security/tutorial007.py!}
```

👉 🔜 🎏:

```Python
if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"):
    # Return some error
    ...
```

✋️ ⚙️ `secrets.compare_digest()` ⚫️ 🔜 🔐 🛡 🆎 👊 🤙 "🕰 👊".

    # Return some error
    ...
```

但使用 `secrets.compare_digest()`，可以防御**时差攻击**，更加安全。

### 时差攻击

什么是**时差攻击**？

假设攻击者试图猜出用户名与密码。

他们发送用户名为 `johndoe`，密码为 `love123`  的请求。

然后，Python 代码执行如下操作：

```Python
if "johndoe" == "stanleyjobson" and "love123" == "swordfish":
    ...
```

{* ../../docs_src/security/tutorial007_an_py39.py hl[1,12:24] *}

Dies wäre das gleiche wie:

```Python
if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"):
    # Einen Error zurückgeben
    ...
```

{* ../../docs_src/security/tutorial007_an_py39.py hl[1,12:24] *}

This would be similar to:

```Python
if not (credentials.username == "stanleyjobson") or not (credentials.password == "swordfish"):
    # Return some error
    ...
```