}

    @Test
    public void test_escapeLDAPSearchFilter_withParentheses() {
        LdapManager ldapManager = new LdapManager();
        ldapManager.init();

        // Parentheses should be escaped (prevents filter injection)
        assertEquals("\\28", ldapManager.escapeLDAPSearchFilter("("));
        assertEquals("\\29", ldapManager.escapeLDAPSearchFilter(")"));

  @CanIgnoreReturnValue
  public B named(String name) {
    checkArgument(
        !name.contains("("),
        "Eclipse hides all characters after "
            + "'('; please use '[]' or other characters instead of parentheses");
    this.name = name;
    return self();
  }

  public String getName() {
    return name;
  }

  // Test suppression

  private final Set<Method> suppressedTests = new HashSet<>();

  @CanIgnoreReturnValue
  public B named(String name) {
    checkArgument(
        !name.contains("("),
        "Eclipse hides all characters after "
            + "'('; please use '[]' or other characters instead of parentheses");
    this.name = name;
    return self();
  }

  public String getName() {
    return name;
  }

  // Test suppression

  private final Set<Method> suppressedTests = new HashSet<>();

        // Asterisk injection attempt
        assertEquals("cn=admin\\2a,dc=example,dc=com", fessConfig.getLdapSecurityPrincipal("admin*"));

        // Parentheses injection attempt
        assertEquals("cn=admin\\29\\28cn=\\2a,dc=example,dc=com", fessConfig.getLdapSecurityPrincipal("admin)(cn=*"));

        // Backslash

Vous ne donnez à `Depends` qu’un seul paramètre.

Ce paramètre doit être quelque chose comme une fonction.

Vous ne l’appelez pas directement (n’ajoutez pas de parenthèses à la fin), vous le passez simplement en paramètre à `Depends()`.

Et cette fonction prend des paramètres de la même manière que les fonctions de chemins d’accès.

/// tip | Astuce

of an "if", "for", or "switch" statement, and the composite literal
is not enclosed in parentheses, square brackets, or curly braces.
In this rare case, the opening brace of the literal is erroneously parsed
as the one introducing the block of statements. To resolve the ambiguity,
the composite literal must appear within parentheses.
</p>

<pre>
if x == (T{a,b,c}[i]) { … }
if (x == T{a,b,c}[i]) { … }
</pre>

You only give `Depends` a single parameter.

This parameter must be something like a function.

You **don't call it** directly (don't add the parenthesis at the end), you just pass it as a parameter to `Depends()`.

And that function takes parameters in the same way that *path operation functions* do.

/// tip

Le das a `Depends` un solo parámetro.

Este parámetro debe ser algo como una función.

**No la llames** directamente (no agregues los paréntesis al final), solo pásala como un parámetro a `Depends()`.

Y esa función toma parámetros de la misma manera que las *path operation functions*.

/// tip | Consejo

Você fornece um único parâmetro para `Depends`.

Esse parâmetro deve ser algo como uma função.

Você **não chama a função** diretamente (não adicione os parênteses no final), apenas a passe como parâmetro de `Depends()`.

E essa função vai receber os parâmetros da mesma forma que uma *função de operação de rota*.

/// tip | Dica

		haveConstant = true
	case '(':
		// Could be parenthesized expression or (R). Must be something, though.
		tok := p.next()
		if tok.ScanToken == scanner.EOF {
			p.errorf("missing right parenthesis")
			return
		}
		rname := tok.String()
		p.back()
		haveConstant = !p.atStartOfRegister(rname)
		if !haveConstant {
			p.back() // Put back the '('.
		}
	}
	if haveConstant {
		p.back()