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Results 1 - 2 of 2 for log1p (0.01 sec)
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guava-tests/test/com/google/common/math/BigIntegerMathTest.java
@GwtIncompatible // TODO public void testLog10HalfEven() { for (BigInteger x : POSITIVE_BIGINTEGER_CANDIDATES) { int halfEven = BigIntegerMath.log10(x, HALF_EVEN); // Now figure out what rounding mode we should behave like (it depends if FLOOR was // odd/even). boolean floorWasEven = (BigIntegerMath.log10(x, FLOOR) & 1) == 0;
Registered: Fri Dec 26 12:43:10 UTC 2025 - Last Modified: Wed Nov 19 01:35:24 UTC 2025 - 27.1K bytes - Viewed (0) -
guava/src/com/google/common/math/LongMath.java
* can narrow the possible floor(log10(x)) values to two. For example, if floor(log2(x)) is 6, * then 64 <= x < 128, so floor(log10(x)) is either 1 or 2. */ int y = maxLog10ForLeadingZeros[Long.numberOfLeadingZeros(x)]; /* * y is the higher of the two possible values of floor(log10(x)). If x < 10^y, then we want the
Registered: Fri Dec 26 12:43:10 UTC 2025 - Last Modified: Mon Nov 03 21:01:09 UTC 2025 - 46.8K bytes - Viewed (0)