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Results 1 - 2 of 2 for log1p (0.01 sec)

  1. guava-tests/test/com/google/common/math/BigIntegerMathTest.java

      @GwtIncompatible // TODO
      public void testLog10HalfEven() {
        for (BigInteger x : POSITIVE_BIGINTEGER_CANDIDATES) {
          int halfEven = BigIntegerMath.log10(x, HALF_EVEN);
          // Now figure out what rounding mode we should behave like (it depends if FLOOR was
          // odd/even).
          boolean floorWasEven = (BigIntegerMath.log10(x, FLOOR) & 1) == 0;
    Registered: Fri Dec 26 12:43:10 UTC 2025
    - Last Modified: Wed Nov 19 01:35:24 UTC 2025
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  2. guava/src/com/google/common/math/LongMath.java

         * can narrow the possible floor(log10(x)) values to two. For example, if floor(log2(x)) is 6,
         * then 64 <= x < 128, so floor(log10(x)) is either 1 or 2.
         */
        int y = maxLog10ForLeadingZeros[Long.numberOfLeadingZeros(x)];
        /*
         * y is the higher of the two possible values of floor(log10(x)). If x < 10^y, then we want the
    Registered: Fri Dec 26 12:43:10 UTC 2025
    - Last Modified: Mon Nov 03 21:01:09 UTC 2025
    - 46.8K bytes
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