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Results 1 - 1 of 1 for ln0 (0.1 sec)

  1. src/net/net.go

    		p = p[n0:]
    		n += n0
    	}
    	if len(*v) == 0 {
    		err = io.EOF
    	}
    	return
    }
    
    func (v *Buffers) consume(n int64) {
    	for len(*v) > 0 {
    		ln0 := int64(len((*v)[0]))
    		if ln0 > n {
    			(*v)[0] = (*v)[0][n:]
    			return
    		}
    		n -= ln0
    		(*v)[0] = nil
    		*v = (*v)[1:]
    	}
    Registered: Wed Jun 12 16:32:35 UTC 2024
    - Last Modified: Wed May 29 17:58:53 UTC 2024
    - 26.8K bytes
    - Viewed (0)
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