new EqualsTester()
        .addEqualityGroup(STR_TO_LONG, STR_TO_LONG.reverse().reverse())
        .addEqualityGroup(STR_TO_LONG.reverse(), STR_TO_LONG.reverse())
        .testEquals();
  }

  public void testReverseReverse() {
    Converter<String, Long> converter = STR_TO_LONG;
    assertEquals(converter, converter.reverse().reverse());
  }

    MutableGraph<Integer> graph =
        GraphBuilder.directed()
            .nodeOrder(ElementOrder.sorted(Ordering.<Integer>natural().reverse()))
            .build();

    addNodes(graph);

    assertThat(graph.nodeOrder())
        .isEqualTo(ElementOrder.sorted(Ordering.<Integer>natural().reverse()));
    assertThat(graph.nodes()).containsExactly(4, 3, 1).inOrder();
  }

  // Edge order tests

  @Test

    Arrays.sort(array, fromIndex, toIndex);
    reverse(array, fromIndex, toIndex);
  }

  /**
   * Reverses the elements of {@code array}. This is equivalent to {@code
   * Collections.reverse(Ints.asList(array))}, but is likely to be more efficient.
   *
   * @since 23.1
   */
  public static void reverse(int[] array) {
    checkNotNull(array);
    reverse(array, 0, array.length);
  }

  /**

 *       returned)
 * </ol>
 *
 * <p>Alas, {@link #reverse} is a little different. As you read backwards through a chain and
 * encounter a call to {@code reverse}, continue working backwards until a result is determined, and
 * then reverse that result.
 *
 * <h3>Additional notes</h3>
 *

 *       returned)
 * </ol>
 *
 * <p>Alas, {@link #reverse} is a little different. As you read backwards through a chain and
 * encounter a call to {@code reverse}, continue working backwards until a result is determined, and
 * then reverse that result.
 *
 * <h3>Additional notes</h3>
 *

            .build();
    assertMapEquals(map, "two", 2, "three", 3, "one", 1, "four", 4, "five", 5);
    assertEquals(Ordering.<String>natural().reverse(), map.comparator());
  }

  public void testBuilderComparator() {
    Comparator<String> comparator = Ordering.<String>natural().reverse();
    ImmutableSortedMap<String, Integer> map =
        new ImmutableSortedMap.Builder<String, Integer>(comparator)
            .put("one", 1)

        // The hardware is big-endian, so we need to reverse the order of the bytes.
        return Long.reverseBytes(bigEndian);
      }

      @Override
      public void putLongLittleEndian(byte[] array, int offset, long value) {
        // Reverse the order of the bytes before storing, since we're on big-endian hardware.

  }

  public void testReverse() {
    Ordering<Number> reverseOrder = numberOrdering.reverse();
    testComparator(reverseOrder, Integer.MAX_VALUE, 1, 0, -1, Integer.MIN_VALUE);

    new EqualsTester()
        .addEqualityGroup(reverseOrder, numberOrdering.reverse())
        .addEqualityGroup(Ordering.natural().reverse())
        .addEqualityGroup(Collections.reverseOrder())
        .testEquals();
  }

  }

  public void testReverse() {
    Ordering<Number> reverseOrder = numberOrdering.reverse();
    testComparator(reverseOrder, Integer.MAX_VALUE, 1, 0, -1, Integer.MIN_VALUE);

    new EqualsTester()
        .addEqualityGroup(reverseOrder, numberOrdering.reverse())
        .addEqualityGroup(Ordering.natural().reverse())
        .addEqualityGroup(Collections.reverseOrder())
        .testEquals();
  }

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