public static int min(int... array) {
    checkArgument(array.length > 0);
    int min = array[0];
    for (int i = 1; i < array.length; i++) {
      if (array[i] < min) {
        min = array[i];
      }
    }
    return min;
  }

  /**
   * Returns the greatest value present in {@code array}.
   *
   * @param array a <i>nonempty</i> array of {@code int} values

          swap(array, from, to);
        }
        return array[k];
      } else {
        int midIndex = (from + to) >>> 1;
        // Choose the median of the elements at the from, to and mid indexes,
        // and rearrange so that array[from]<=array[from+1], and
        // array[to] => array[from + 1].

        swap(array, midIndex, from + 1);

        if (array[from] > array[to]) {

    Arrays.sort(array, fromIndex, toIndex);
    reverse(array, fromIndex, toIndex);
  }

  /**
   * Reverses the elements of {@code array}. This is equivalent to {@code
   * Collections.reverse(Floats.asList(array))}, but is likely to be more efficient.
   *
   * @since 23.1
   */
  public static void reverse(float[] array) {
    checkNotNull(array);
    reverse(array, 0, array.length);
  }

  /**

    Arrays.sort(array, fromIndex, toIndex);
    reverse(array, fromIndex, toIndex);
  }

  /**
   * Reverses the elements of {@code array}. This is equivalent to {@code
   * Collections.reverse(Doubles.asList(array))}, but is likely to be more efficient.
   *
   * @since 23.1
   */
  public static void reverse(double[] array) {
    checkNotNull(array);
    reverse(array, 0, array.length);
  }

    if (toLessThanMid == midLessThanFrom) {
      // Either array[to] < array[mid] < array[from] or array[from] <= array[mid] <= array[to].
      swap(array, mid, from);
    } else if (toLessThanMid != toLessThanFrom) {
      // Either array[from] <= array[to] < array[mid] or array[mid] <= array[to] < array[from].
      swap(array, from, to);
    }

          swap(array, from, to);
        }
        return array[k];
      } else {
        int midIndex = (from + to) >>> 1;
        // Choose the median of the elements at the from, to and mid indexes,
        // and rearrange so that array[from]<=array[from+1], and
        // array[to] => array[from + 1].

        swap(array, midIndex, from + 1);

        if (array[from] > array[to]) {

   *     in the array according to {@link #compare}
   * @throws IllegalArgumentException if {@code array} is empty
   */
  public static int max(int... array) {
    checkArgument(array.length > 0);
    int max = flip(array[0]);
    for (int i = 1; i < array.length; i++) {
      int next = flip(array[i]);
      if (next > max) {
        max = next;
      }
    }

   * array is that of the specified array. The returned array elements are in no particular order.
   * If the queue fits in the specified array, it is returned therein. Otherwise, a new array is
   * allocated with the runtime type of the specified array and the size of this queue.
   *
   * <p>If this queue fits in the specified array with room to spare (i.e., the array has more

  }

  /**
   * Returns an array containing all of the elements in this queue, in proper sequence; the runtime
   * type of the returned array is that of the specified array. If the queue fits in the specified
   * array, it is returned therein. Otherwise, a new array is allocated with the runtime type of the
   * specified array and the size of this queue.
   *

    assertThat(Bytes.toArray(bytes)).isEqualTo(array);
    assertThat(Bytes.toArray(shorts)).isEqualTo(array);
    assertThat(Bytes.toArray(ints)).isEqualTo(array);
    assertThat(Bytes.toArray(floats)).isEqualTo(array);
    assertThat(Bytes.toArray(longs)).isEqualTo(array);
    assertThat(Bytes.toArray(doubles)).isEqualTo(array);
  }