- Sort Score
- Num 10 results
- Language All
Results 1 - 2 of 2 for sqrtCandidate (0.51 seconds)
-
lib/fips140/v1.26.0.zip
and x can overlap. func {{.p}}Sqrt(e, x *{{ .Element }}) (isSquare bool) { candidate := new({{ .Element }}) {{.p}}SqrtCandidate(candidate, x) square := new({{ .Element }}).Square(candidate) if square.Equal(x) != 1 { return false } e.Set(candidate) return true } ` const tmplAddchain = ` // sqrtCandidate sets z to a square root candidate for x. z and x must not overlap. func sqrtCandidate(z, x *Element) { // Since p = 3 mod 4, exponentiation by (p + 1) / 4 yields a square root candidate. // // The sequence...Created: Tue Apr 07 11:13:11 GMT 2026 - Last Modified: Thu Jan 08 17:58:32 GMT 2026 - 660.3K bytes - Click Count (0) -
lib/fips140/v1.0.0-c2097c7c.zip
and x can overlap. func {{.p}}Sqrt(e, x *{{ .Element }}) (isSquare bool) { candidate := new({{ .Element }}) {{.p}}SqrtCandidate(candidate, x) square := new({{ .Element }}).Square(candidate) if square.Equal(x) != 1 { return false } e.Set(candidate) return true } ` const tmplAddchain = ` // sqrtCandidate sets z to a square root candidate for x. z and x must not overlap. func sqrtCandidate(z, x *Element) { // Since p = 3 mod 4, exponentiation by (p + 1) / 4 yields a square root candidate. // // The sequence...Created: Tue Apr 07 11:13:11 GMT 2026 - Last Modified: Thu Sep 25 19:53:19 GMT 2025 - 642.7K bytes - Click Count (0)