expect:
        def union1 = Specs.union(spec1, spec2)
        union1 instanceof OrSpec
        union1.specs == [spec1, spec2]

        def union2 = Specs.union([spec1, spec2])
        union2 instanceof OrSpec
        union2.specs == [spec1, spec2]
    }

    def "union of none is none"() {
        expect:
        Specs.union(Specs.satisfyNone()) == Specs.satisfyNone()

}

func (u *Union) Len() int         { return len(u.terms) }
func (u *Union) Term(i int) *Term { return u.terms[i] }

func (u *Union) Underlying() Type { return u }
func (u *Union) String() string   { return TypeString(u, nil) }

// A Term represents a term in a Union.
type Term term

// NewTerm returns a new union term.
func NewTerm(tilde bool, typ Type) *Term { return &Term{tilde, typ} }

}

func (u *Union) Len() int         { return len(u.terms) }
func (u *Union) Term(i int) *Term { return u.terms[i] }

func (u *Union) Underlying() Type { return u }
func (u *Union) String() string   { return TypeString(u, nil) }

// A Term represents a term in a [Union].
type Term term

// NewTerm returns a new union term.
func NewTerm(tilde bool, typ Type) *Term { return &Term{tilde, typ} }

import java.util.Set;
import java.util.stream.Collectors;

class Unions {
    private final ExcludeFactory factory;

    public Unions(ExcludeFactory factory) {
        this.factory = factory;
    }

    /**
     * Tries to compute an union of 2 specs.
     * The result MUST be a simplification, otherwise this method returns null.
     */

public class NormalizingExcludeFactory extends DelegatingExcludeFactory {
    private final Intersections intersections;
    private final Unions unions;

    public NormalizingExcludeFactory(ExcludeFactory delegate) {
        super(delegate);
        this.intersections = new Intersections(this);
        this.unions = new Unions(this);
    }

    @Override
    public ExcludeSpec anyOf(ExcludeSpec one, ExcludeSpec two) {

    ```

## `Union` ⚖️ `anyOf`

👆 💪 📣 📨 `Union` 2️⃣ 🆎, 👈 ⛓, 👈 📨 🔜 🙆 2️⃣.

⚫️ 🔜 🔬 🗄 ⏮️ `anyOf`.

👈, ⚙️ 🐩 🐍 🆎 🔑 <a href="https://docs.python.org/3/library/typing.html#typing.Union" class="external-link" target="_blank">`typing.Union`</a>:

!!! note

				terms = tset2.terms
			case *types.TypeParam, *types.Union:
				// A stand-alone type parameter or union is not permitted as union
				// term.
				return nil, fmt.Errorf("invalid union term %T", t)
			default:
				if t.Type() == types.Typ[types.Invalid] {
					continue
				}
				terms = termlist{{t.Tilde(), t.Type()}}
			}
			tset.terms = tset.terms.union(terms)
			if len(tset.terms) > maxTermCount {

    ```

## `Union` or `anyOf`

You can declare a response to be the `Union` of two types, that means, that the response would be any of the two.

It will be defined in OpenAPI with `anyOf`.

To do that, use the standard Python type hint <a href="https://docs.python.org/3/library/typing.html#typing.Union" class="external-link" target="_blank">`typing.Union`</a>:

!!! note

    ```

## `Union` или `anyOf`

Вы можете определить ответ как `Union` из двух типов. Это означает, что ответ должен соответствовать одному из них.

Он будет определён в OpenAPI как `anyOf`.

Для этого используйте стандартные аннотации типов в Python <a href="https://docs.python.org/3/library/typing.html#typing.Union" class="external-link" target="_blank">`typing.Union`</a>:

!!! note "Примечание"

    ```

## `Union` ou `anyOf`

Você pode declarar uma resposta como o `Union` de dois tipos, o que significa que a resposta seria qualquer um dos dois.

Isso será definido no OpenAPI com `anyOf`.

Para fazer isso, use a dica de tipo padrão do Python <a href="https://docs.python.org/3/library/typing.html#typing.Union" class="external-link" target="_blank">`typing.Union`</a>:

!!! note