import static com.google.common.collect.Iterables.find;
import static com.google.common.collect.Iterables.frequency;
import static com.google.common.collect.Iterables.getOnlyElement;
import static com.google.common.collect.Iterables.mergeSorted;
import static com.google.common.collect.Iterables.removeIf;
import static com.google.common.collect.Iterables.skip;
import static com.google.common.collect.Iterables.tryFind;

   * compare as equal, A will be returned before B if iterable 1 was passed before iterable 2.
   *
   * @since 11.0
   */
  public static <T extends @Nullable Object> Iterable<T> mergeSorted(
      Iterable<? extends Iterable<? extends T>> iterables, Comparator<? super T> comparator) {
    checkNotNull(iterables, "iterables");
    checkNotNull(comparator, "comparator");
    Iterable<T> iterable =

   * compare as equal, A will be returned before B if iterable 1 was passed before iterable 2.
   *
   * @since 11.0
   */
  public static <T extends @Nullable Object> Iterable<T> mergeSorted(
      Iterable<? extends Iterable<? extends T>> iterables, Comparator<? super T> comparator) {
    checkNotNull(iterables, "iterables");
    checkNotNull(comparator, "comparator");
    Iterable<T> iterable =

    // When elements compare as equal (both C's have same letter), our merge should always return C1
    // before C2, since C1 is from the first iterator.

    Iterator<TestDatum> merged =
        Iterators.mergeSorted(ImmutableList.of(left.iterator(), right.iterator()), comparator);

    ImmutableList<TestDatum> result = ImmutableList.copyOf(merged);

    assertThat(result)
        .containsExactly(

   * compare as equal, A will be returned before B if iterator 1 was passed before iterator 2.
   *
   * @since 11.0
   */
  public static <T extends @Nullable Object> UnmodifiableIterator<T> mergeSorted(
      Iterable<? extends Iterator<? extends T>> iterators, Comparator<? super T> comparator) {
    checkNotNull(iterators, "iterators");
    checkNotNull(comparator, "comparator");