public void testIn_compilesWithExplicitSupertype() {
    Collection<Number> nums = ImmutableSet.of();
    Predicate<Number> p1 = Predicates.in(nums);
    Predicate<Object> p2 = Predicates.<Object>in(nums);
    // The next two lines are not expected to compile.
    // Predicate<Integer> p3 = Predicates.in(nums);
    // Predicate<Integer> p4 = Predicates.<Integer>in(nums);
  }

  @J2ktIncompatible
  @GwtIncompatible // NullPointerTester

  }

  static BigInteger listProduct(List<BigInteger> nums) {
    return listProduct(nums, 0, nums.size());
  }

  static BigInteger listProduct(List<BigInteger> nums, int start, int end) {
    switch (end - start) {
      case 0:
        return BigInteger.ONE;
      case 1:
        return nums.get(start);
      case 2:
        return nums.get(start).multiply(nums.get(start + 1));
      case 3:

        };
    assertEquals(2, Iterables.size(iterable));
  }

  @SuppressWarnings("serial")
  public void testSize_collection_doesntIterate() {
    List<Integer> nums = asList(1, 2, 3, 4, 5);
    List<Integer> collection =
        new ArrayList<Integer>(nums) {
          @Override
          public Iterator<Integer> iterator() {
            throw new AssertionFailedError("Don't iterate me!");
          }
        };

        };
    assertEquals(2, Iterables.size(iterable));
  }

  @SuppressWarnings("serial")
  public void testSize_collection_doesntIterate() {
    List<Integer> nums = asList(1, 2, 3, 4, 5);
    List<Integer> collection =
        new ArrayList<Integer>(nums) {
          @Override
          public Iterator<Integer> iterator() {
            throw new AssertionFailedError("Don't iterate me!");
          }
        };

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        return inputSet.keySet().equals(that.inputSet.keySet());
      }
      return super.equals(obj);
    }

    @Override
    public int hashCode() {
      /*
       * The sum of the sums of the hash codes in each subset is just the sum of
       * each input element's hash code times the number of sets that element
       * appears in. Each element appears in exactly half of the 2^n sets, so:
       */