}
		} else {
			// If bytealg.Index is not available a brute force search is
			// ~1.5-3x faster than Rabin-Karp since n is small.
			c0 := b[last]
			c1 := b[last-1] // There are at least 2 chars to match
		loop:
			for ; i < len(s); i++ {
				if s[i] == c0 && s[i-1] == c1 {
					for k := 2; k < n; k++ {
						if s[i-k] != b[last-k] {
							continue loop
						}
					}
					return i - last
				}
			}
		}