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Results 1 - 3 of 3 for 0xFFFD (0.04 sec)

  1. guava-tests/test/com/google/common/xml/XmlEscapersTest.java

            // and everything else is replaced with FFFD.
            assertEscaping(xmlEscaper, "\uFFFD", ch);
          }
        }
    
        // Test _all_ allowed characters (including surrogate values).
        for (char ch = 0x20; ch <= 0xFFFD; ch++) {
          // There are a small number of cases to consider, so just do it manually.
          if (ch == '&') {
            assertEscaping(xmlEscaper, "&amp;", ch);
          } else if (ch == '<') {
    Registered: Fri Dec 26 12:43:10 UTC 2025
    - Last Modified: Fri Dec 05 22:03:28 UTC 2025
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  2. src/bytes/bytes_test.go

    	{" ", []rune{32}, false},
    	{"ABC", []rune{65, 66, 67}, false},
    	{"abc", []rune{97, 98, 99}, false},
    	{"\u65e5\u672c\u8a9e", []rune{26085, 26412, 35486}, false},
    	{"ab\x80c", []rune{97, 98, 0xFFFD, 99}, true},
    	{"ab\xc0c", []rune{97, 98, 0xFFFD, 99}, true},
    }
    
    func TestRunes(t *testing.T) {
    	for _, tt := range RunesTests {
    		tin := []byte(tt.in)
    		a := Runes(tin)
    		if !slices.Equal(a, tt.out) {
    Registered: Tue Dec 30 11:13:12 UTC 2025
    - Last Modified: Tue Dec 23 23:54:14 UTC 2025
    - 62.9K bytes
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  3. doc/go_spec.html

    and the second value, of type <code>rune</code>, will be the value of
    the corresponding code point. If the iteration encounters an invalid
    UTF-8 sequence, the second value will be <code>0xFFFD</code>,
    the Unicode replacement character, and the next iteration will advance
    a single byte in the string.
    </li>
    
    <li>
    The iteration order over maps is not specified
    Registered: Tue Dec 30 11:13:12 UTC 2025
    - Last Modified: Tue Dec 02 23:07:19 UTC 2025
    - 286.5K bytes
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