assertEquals(GeneralRange.all(ORDERING.reverse()), GeneralRange.all(ORDERING).reverse());
    assertEquals(
        GeneralRange.downTo(ORDERING.reverse(), 3, CLOSED),
        GeneralRange.upTo(ORDERING, 3, CLOSED).reverse());
    assertEquals(
        GeneralRange.upTo(ORDERING.reverse(), 3, OPEN),
        GeneralRange.downTo(ORDERING, 3, OPEN).reverse());
    assertEquals(

    Comparator<Integer> natural = Ordering.natural();
    Comparator<Integer> reverse = Collections.reverseOrder(natural);
    assertThat(Comparators.min(1, 2, reverse)).isEqualTo(2);
    assertThat(Comparators.min(2, 1, reverse)).isEqualTo(2);
    assertThat(Comparators.max(1, 2, reverse)).isEqualTo(1);
    assertThat(Comparators.max(2, 1, reverse)).isEqualTo(1);
  }

  /**

    Comparator<Integer> natural = Ordering.natural();
    Comparator<Integer> reverse = Collections.reverseOrder(natural);
    assertThat(Comparators.min(1, 2, reverse)).isEqualTo(2);
    assertThat(Comparators.min(2, 1, reverse)).isEqualTo(2);
    assertThat(Comparators.max(1, 2, reverse)).isEqualTo(1);
    assertThat(Comparators.max(2, 1, reverse)).isEqualTo(1);
  }

  /**

            .build();
    assertMapEquals(map, "two", 2, "three", 3, "one", 1, "four", 4, "five", 5);
    assertEquals(Ordering.<String>natural().reverse(), map.comparator());
  }

  public void testBuilderComparator() {
    Comparator<String> comparator = Ordering.<String>natural().reverse();
    ImmutableSortedMap<String, Integer> map =
        new ImmutableSortedMap.Builder<String, Integer>(comparator)
            .put("one", 1)

  }

  public void testReverse() {
    Ordering<Number> reverseOrder = numberOrdering.reverse();
    Helpers.testComparator(reverseOrder, Integer.MAX_VALUE, 1, 0, -1, Integer.MIN_VALUE);

    new EqualsTester()
        .addEqualityGroup(reverseOrder, numberOrdering.reverse())
        .addEqualityGroup(Ordering.natural().reverse())
        .addEqualityGroup(Collections.reverseOrder())
        .testEquals();
  }

  }

  public void testReverse() {
    Ordering<Number> reverseOrder = numberOrdering.reverse();
    Helpers.testComparator(reverseOrder, Integer.MAX_VALUE, 1, 0, -1, Integer.MIN_VALUE);

    new EqualsTester()
        .addEqualityGroup(reverseOrder, numberOrdering.reverse())
        .addEqualityGroup(Ordering.natural().reverse())
        .addEqualityGroup(Collections.reverseOrder())
        .testEquals();
  }

                    for (int i = elements.length - 1; i >= 0; i--) {
                      list.add(elements[i]);
                    }
                    return Lists.reverse(list);
                  }
                })
            .named("Lists.reverse[ArrayList]")
            .withFeatures(
                CollectionSize.ANY,
                CollectionFeature.ALLOWS_NULL_VALUES,
                ListFeature.GENERAL_PURPOSE)

    if (ranges.isEmpty()) {
      return ImmutableMap.of();
    }
    RegularImmutableSortedSet<Range<K>> rangeSet =
        new RegularImmutableSortedSet<>(ranges.reverse(), Range.<K>rangeLexOrdering().reverse());
    return new ImmutableSortedMap<>(rangeSet, values.reverse());
  }

  @Override
  public ImmutableRangeMap<K, V> subRangeMap(final Range<K> range) {
    if (checkNotNull(range).isEmpty()) {

    return offset + size;
  }

  /**
   * Returns a view of this immutable list in reverse order. For example, {@code ImmutableList.of(1,
   * 2, 3).reverse()} is equivalent to {@code ImmutableList.of(3, 2, 1)}.
   *
   * @return a view of this immutable list in reverse order
   * @since 7.0
   */
  public ImmutableList<E> reverse() {
    return (size() <= 1) ? this : new ReverseImmutableList<E>(this);
  }

  public UnmodifiableIterator<E> iterator() {
    return elements.iterator();
  }

  @GwtIncompatible // NavigableSet
  @Override
  public UnmodifiableIterator<E> descendingIterator() {
    return elements.reverse().iterator();
  }

  @Override
  public int size() {
    return elements.size();
  }

  @Override
  public boolean contains(@CheckForNull Object o) {
    try {