}
	}
}

func TestLastIndexByte(t *testing.T) {
	testCases := []BinOpTest{
		{"", "q", -1},
		{"abcdef", "q", -1},
		{"abcdefabcdef", "a", len("abcdef")},      // something in the middle
		{"abcdefabcdef", "f", len("abcdefabcde")}, // last byte
		{"zabcdefabcdef", "z", 0},                 // first byte
		{"a☺b☻c☹d", "b", len("a☺")},               // non-ascii
	}

	haveConstant := false
	switch tok.ScanToken {
	case scanner.Int, scanner.Float, scanner.String, scanner.Char, '+', '-', '~':
		haveConstant = true
	case '(':
		// Could be parenthesized expression or (R). Must be something, though.
		tok := p.next()
		if tok.ScanToken == scanner.EOF {
			p.errorf("missing right parenthesis")
			return
		}
		rname := tok.String()
		p.back()
		haveConstant = !p.atStartOfRegister(rname)

</p>

<p>
If the channel were buffered (e.g., <code>c = make(chan int, 1)</code>)
then the program would not be guaranteed to print
<code>"hello, world"</code>.  (It might print the empty string,
crash, or do something else.)
</p>

<p class="rule">
The <i>k</i>th receive on a channel with capacity <i>C</i> is synchronized before the completion of the <i>k</i>+<i>C</i>th send from that channel completes.
</p>

<p>