*     ImmutableSetMultimap.<Character, Character>builder()
   *         .putAll('b', Arrays.asList('a', 'n', 'a', 'n', 'a'))
   *         .putAll('a', Arrays.asList('p', 'p', 'l', 'e'))
   *         .putAll('c', Arrays.asList('a', 'r', 'r', 'o', 't'))
   *         .putAll('a', Arrays.asList('s', 'p', 'a', 'r', 'a', 'g', 'u', 's'))
   *         .putAll('c', Arrays.asList('h', 'e', 'r', 'r', 'y'))
   *         .build();
   *

   * they're defined above -- including logic to add and subtract 1 to map between the values stored
   * in the predecessor/successor arrays and the indexes in the elements array that they identify.
   */

    }
  }

  private void recurse(int level) {
    // We're going to reuse the stimuli array 3^steps times by overwriting it
    // in a recursive loop.  Sneaky.
    if (level == stimuli.length) {
      // We've filled the array.
      compareResultsForThisListOfStimuli();
    } else {
      // Keep recursing to fill the array.
      for (Stimulus<E, ? super I> stimulus : getStimulusValues()) {
        stimuli[level] = stimulus;

    }
  }

  /** Returns the {@code Class} object of arrays with {@code componentType}. */
  static Class<?> getArrayClass(Class<?> componentType) {
    // TODO(user): This is not the most efficient way to handle generic
    // arrays, but is there another way to extract the array class in a
    // non-hacky way (i.e. using String value class names- "[L...")?
    return Array.newInstance(componentType, 0).getClass();
  }

import static com.google.common.collect.testing.Helpers.assertEqualInOrder;
import static com.google.common.collect.testing.Platform.format;
import static java.util.Arrays.asList;
import static java.util.Collections.unmodifiableSet;
import static junit.framework.Assert.assertEquals;
import static junit.framework.Assert.assertFalse;
import static junit.framework.Assert.assertTrue;

import com.google.common.annotations.GwtIncompatible;
import com.google.common.annotations.J2ktIncompatible;
import com.google.common.annotations.VisibleForTesting;
import java.util.AbstractMap;
import java.util.Arrays;
import java.util.Map.Entry;
import javax.annotation.CheckForNull;
import org.checkerframework.checker.nullness.qual.Nullable;

/**
 * A hash-based implementation of {@link ImmutableMap}.
 *

    Object[] array = new Object[12 + others.length];
    array[0] = e1;
    array[1] = e2;
    array[2] = e3;
    array[3] = e4;
    array[4] = e5;
    array[5] = e6;
    array[6] = e7;
    array[7] = e8;
    array[8] = e9;
    array[9] = e10;
    array[10] = e11;
    array[11] = e12;
    System.arraycopy(others, 0, array, 12, others.length);
    return construct(array);

          // there's a way around creating the separate sortedKeys array, and if we're allocating
          // one array of size n, we might as well allocate two -- to say nothing of the allocation
          // done in Arrays.sort.
          for (int i = 0; i < size; i++) {
            // We're careful to put only K instances in.
            if (i > 0 && comparator.compare((K) sortedKeys[i - 1], (K) sortedKeys[i]) == 0) {

    final int[] o;
    int j;

    PermutationIterator(List<E> list) {
      this.list = new ArrayList<>(list);
      int n = list.size();
      c = new int[n];
      o = new int[n];
      Arrays.fill(c, 0);
      Arrays.fill(o, 1);
      j = Integer.MAX_VALUE;
    }

    @Override
    @CheckForNull
    protected List<E> computeNext() {
      if (j <= 0) {
        return endOfData();
      }

      if (!original.isPartialView()) {
        return original;
      }
    }
    @SuppressWarnings("unchecked") // elements only contains E's; it's safe.
    E[] array = (E[]) Iterables.toArray(elements);
    return construct(comparator, array.length, array);
  }

  /**
   * Returns an immutable sorted set containing the given elements sorted by the given {@code