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Results 1 - 4 of 4 for onabort (0.09 seconds)

  1. RELEASE.md

    *   Fixes a memory leak when a graph node is invalid
        ([CVE-2022-23578](https://cve.mitre.org/cgi-bin/cvename.cgi?name=CVE-2022-23578))
    *   Fixes an abort caused by allocating a vector that is too large
        ([CVE-2022-23580](https://cve.mitre.org/cgi-bin/cvename.cgi?name=CVE-2022-23580))
    *   Fixes multiple `CHECK`-failures during Grappler's `IsSimplifiableReshape`
    Created: Tue Apr 07 12:39:13 GMT 2026
    - Last Modified: Mon Mar 30 18:31:38 GMT 2026
    - 746.5K bytes
    - Click Count (3)
  2. src/cmd/asm/internal/asm/testdata/amd64enc.s

    	WRGSBASEQ DX                            // f3480faeda
    	WRGSBASEQ R11                           // f3490faedb
    	WRMSR                                   // 0f30
    	WRPKRU                                  // 0f01ef
    	XABORT $7                               // c6f807
    	XADDW DX, (BX)                          // 660fc113
    	XADDW R11, (BX)                         // 66440fc11b
    	XADDW DX, (R11)                         // 66410fc113
    Created: Tue Apr 07 11:13:11 GMT 2026
    - Last Modified: Fri Oct 08 21:38:44 GMT 2021
    - 581.9K bytes
    - Click Count (1)
  3. lib/fips140/v1.26.0.zip

    it-plv/fiat-crypto/pull/333/files. // // Following the proof linked in the PR above, the changes are: // // 1. Negate [B] and [C] so they are positive. The invariant now involves a // subtraction. // 2. If step 2 (both [x] and [y] are even) runs, abort immediately. This // case needs to be handled by the caller. // 3. Subtract copies of [x] and [y] as needed in step 6 (both [u] and [v] // are odd) so coefficients stay in bounds. // 4. Replace the [u >= v] check with [u > v]. This changes the end...
    Created: Tue Apr 07 11:13:11 GMT 2026
    - Last Modified: Thu Jan 08 17:58:32 GMT 2026
    - 660.3K bytes
    - Click Count (0)
  4. lib/fips140/v1.0.0-c2097c7c.zip

    it-plv/fiat-crypto/pull/333/files. // // Following the proof linked in the PR above, the changes are: // // 1. Negate [B] and [C] so they are positive. The invariant now involves a // subtraction. // 2. If step 2 (both [x] and [y] are even) runs, abort immediately. This // case needs to be handled by the caller. // 3. Subtract copies of [x] and [y] as needed in step 6 (both [u] and [v] // are odd) so coefficients stay in bounds. // 4. Replace the [u >= v] check with [u > v]. This changes the end...
    Created: Tue Apr 07 11:13:11 GMT 2026
    - Last Modified: Thu Sep 25 19:53:19 GMT 2025
    - 642.7K bytes
    - Click Count (0)
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