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  1. RELEASE.md

    Hinsu, snadampal, Sohaib Iftikhar, Soowon Jeong, spiao, Srijan Upadhyay, stevemcgregory, Subham Soni, Subhankar Shah, Swachhand Lokhande, Tai Ly, TensorFlower Gardener, Terry Heo, Terry Sun, Terry Tao, Theotime Combes, Thomas Joerg, Thomas Köppe, Tiago Quelhas, TJ Xu, Toli Yevtushenko, Tomás Longeri, Tom Hennigan, Tommy Chiang, Tom Natan, Tongfei Guo, Tori Baker, Uwe L. Korn, Vadym Matsishevskyi, Vamsi Manchala, Venkat6871, Victor Stone, Ville Vesilehto, Vitalii Dziuba, Vladimir Belitskiy, Vlad Sytchenko,...
    Created: Tue Apr 07 12:39:13 GMT 2026
    - Last Modified: Mon Mar 30 18:31:38 GMT 2026
    - 746.5K bytes
    - Click Count (3)
  2. docs/en/docs/release-notes.md

    * Add basic setup for Russian translations. PR [#1566](https://github.com/tiangolo/fastapi/pull/1566).
    Created: Sun Apr 05 07:19:11 GMT 2026
    - Last Modified: Fri Apr 03 12:07:04 GMT 2026
    - 631K bytes
    - Click Count (0)
  3. lib/fips140/v1.0.0-c2097c7c.zip

    func p224SqrtCandidate(r, x *fiat.P224Element) { // Since p = 1 mod 4, we can't use the exponentiation by (p + 1) / 4 like // for the other primes. Instead, implement a variation of Tonelli–Shanks. // The constant-time implementation is adapted from Thomas Pornin's ecGFp5. // // https://github.com/pornin/ecgfp5/blob/82325b965/rust/src/field.rs#L337-L385 // p = q*2^n + 1 with q odd -> q = 2^128 - 1 and n = 96 // g^(2^n) = 1 -> g = 11 ^ q (where 11 is the smallest non-square) // GG[j] = g^(2^j) for j...
    Created: Tue Apr 07 11:13:11 GMT 2026
    - Last Modified: Thu Sep 25 19:53:19 GMT 2025
    - 642.7K bytes
    - Click Count (0)
  4. lib/fips140/v1.26.0.zip

    func p224SqrtCandidate(r, x *fiat.P224Element) { // Since p = 1 mod 4, we can't use the exponentiation by (p + 1) / 4 like // for the other primes. Instead, implement a variation of Tonelli–Shanks. // The constant-time implementation is adapted from Thomas Pornin's ecGFp5. // // https://github.com/pornin/ecgfp5/blob/82325b965/rust/src/field.rs#L337-L385 // p = q*2^n + 1 with q odd -> q = 2^128 - 1 and n = 96 // g^(2^n) = 1 -> g = 11 ^ q (where 11 is the smallest non-square) // GG[j] = g^(2^j) for j...
    Created: Tue Apr 07 11:13:11 GMT 2026
    - Last Modified: Thu Jan 08 17:58:32 GMT 2026
    - 660.3K bytes
    - Click Count (0)
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