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okhttp/src/commonJvmAndroid/kotlin/okhttp3/HttpUrl.kt
* component must escape all of its `?` characters, otherwise it could be interpreted as the * start of the URL's query. But within the query and fragment components, the `?` character * doesn't delimit anything and doesn't need to be escaped. * * ```java * HttpUrl url = HttpUrl.parse("http://who-let-the-dogs.out").newBuilder() * .addPathSegment("_Who?_") * .query("_Who?_") * .fragment("_Who?_")
Registered: Fri Dec 26 11:42:13 UTC 2025 - Last Modified: Mon May 05 16:01:00 UTC 2025 - 63.5K bytes - Viewed (0)