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Results 1 - 2 of 2 for dall (0.01 sec)

  1. src/main/resources/suggest_indices/suggest_analyzer.json

            "language":   "indonesian"
          },
          "italian_elision": {
            "type":         "elision",
            "articles": [
              "c", "l", "all", "dall", "dell",
              "nell", "sull", "coll", "pell",
              "gl", "agl", "dagl", "degl", "negl",
              "sugl", "un", "m", "t", "s", "v", "d"
            ]
          },
          "italian_stop": {
            "type":       "stop",
    Registered: Fri Sep 19 09:08:11 UTC 2025
    - Last Modified: Thu Oct 03 02:51:59 UTC 2019
    - 57.3K bytes
    - Viewed (0)
  2. fess-crawler/src/test/resources/ajax/js/jquery-2.1.1.min.js

    =!1)break}else for(e in a)if(d=b.apply(a[e],c),d===!1)break}else if(g){for(;f>e;e++)if(d=b.call(a[e],e,a[e]),d===!1)break}else for(e in a)if(d=b.call(a[e],e,a[e]),d===!1)break;return a},trim:function(a){return null==a?"":(a+"").replace(o,"")},makeArray:function(a,b){var c=b||[];return null!=a&&(s(Object(a))?n.merge(c,"string"==typeof a?[a]:a):f.call(c,a)),c},inArray:function(a,b,c){return null==b?-1:g.call(b,a,c)},merge:function(a,b){for(var c=+b.length,d=0,e=a.length;c>d;d++)a[e++]=b[d];return ...
    Registered: Sun Sep 21 03:50:09 UTC 2025
    - Last Modified: Sun Oct 11 02:16:55 UTC 2015
    - 82.3K bytes
    - Viewed (0)
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