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Results 1 - 4 of 4 for alphabeta (0.14 sec)
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src/encoding/json/decode_test.go
{CaseName: Name(""), in: `{"alpha": "abc", "alphabet": "xyz"}`, ptr: new(U), out: U{Alphabet: "abc"}}, {CaseName: Name(""), in: `{"alpha": "abc", "alphabet": "xyz"}`, ptr: new(U), err: fmt.Errorf("json: unknown field \"alphabet\""), disallowUnknownFields: true}, {CaseName: Name(""), in: `{"alpha": "abc"}`, ptr: new(U), out: U{Alphabet: "abc"}}, {CaseName: Name(""), in: `{"alphabet": "xyz"}`, ptr: new(U), out: U{}},
Registered: Wed Jun 12 16:32:35 UTC 2024 - Last Modified: Thu Apr 11 16:40:14 UTC 2024 - 67.6K bytes - Viewed (0) -
android/guava/src/com/google/common/base/CharMatcher.java
} /** * Determines whether a character is a BMP letter according to {@linkplain * Character#isLetter(char) Java's definition}. If you only care to match letters of the Latin * alphabet, you can use {@code inRange('a', 'z').or(inRange('A', 'Z'))}. * * @deprecated Most letters are supplementary characters; see the class documentation. * @since 19.0 (since 1.0 as constant {@code JAVA_LETTER}) */
Registered: Wed Jun 12 16:38:11 UTC 2024 - Last Modified: Fri Feb 09 15:49:48 UTC 2024 - 53.7K bytes - Viewed (0) -
guava/src/com/google/common/base/CharMatcher.java
} /** * Determines whether a character is a BMP letter according to {@linkplain * Character#isLetter(char) Java's definition}. If you only care to match letters of the Latin * alphabet, you can use {@code inRange('a', 'z').or(inRange('A', 'Z'))}. * * @deprecated Most letters are supplementary characters; see the class documentation. * @since 19.0 (since 1.0 as constant {@code JAVA_LETTER}) */
Registered: Wed Jun 12 16:38:11 UTC 2024 - Last Modified: Fri Feb 09 15:49:48 UTC 2024 - 53.8K bytes - Viewed (0) -
src/regexp/syntax/parse.go
func appendRange(r []rune, lo, hi rune) []rune { // Expand last range or next to last range if it overlaps or abuts. // Checking two ranges helps when appending case-folded // alphabets, so that one range can be expanding A-Z and the // other expanding a-z. n := len(r) for i := 2; i <= 4; i += 2 { // twice, using i=2, i=4 if n >= i { rlo, rhi := r[n-i], r[n-i+1]
Registered: Wed Jun 12 16:32:35 UTC 2024 - Last Modified: Tue Apr 02 13:59:01 UTC 2024 - 52.1K bytes - Viewed (0)