// difference in the resulting rounding. Therefore, we
	// preserve it, and OR (not ADD) it back in. The case
	// that matters is when the eleven discarded bits are
	// equal to 10000000001; that rounds up, and the 1 cannot
	// be lost else it would round down if the LSB of the
	// candidate mantissa is 0.
	cmp := s.newValue2(cvttab.leq, types.Types[types.TBOOL], s.zeroVal(ft), x)
	b := s.endBlock()

1024                int16       1024 is in the set of 16-bit integers
42.0                byte        42 is in the set of unsigned 8-bit integers
1e10                uint64      10000000000 is in the set of unsigned 64-bit integers
2.718281828459045   float32     2.718281828459045 rounds to 2.7182817 which is in the set of float32 values