A2 = A1
)

type (
	B1 string
	B2 B1
	B3 []B1
	B4 B3
)

func f[P any](x P) { … }
</pre>

<p>
The underlying type of <code>string</code>, <code>A1</code>, <code>A2</code>, <code>B1</code>,
and <code>B2</code> is <code>string</code>.
The underlying type of <code>[]B1</code>, <code>B3</code>, and <code>B4</code> is <code>[]B1</code>.

IC"},J:{"2":"E A"},K:{"1":"m","2":"A B C vB HC wB"},L:{"1":"I"},M:{"1":"uB"},N:{"2":"A B"},O:{"1":"xB"},P:{"1":"J k l 1C 2C 3C 4C 5C 6B 6C 7C 8C 9C AD yB BD CD DD"},Q:{"1":"7B"},R:{"1":"ED"},S:{"1":"FD GD"}},B:4,C:"CSS Feature Queries"}});var ag=v((b4,sg)=>{l();function ig(i){return i[i.length-1]}var ng={parse(i){let e=[""],t=[e];for(let r of i){if(r==="("){e=[""],ig(t).push(e),t.push(e);continue}if(r===")"){t.pop(),e=ig(t),e.push("");continue}e[e.length-1]+=r}return t[0]},stringify(i){let e="";for(let...