int p1, p2, l1, l2;

        // if unsure return this method returns true

        p1 = path1.lastIndexOf('/');
        p2 = path2.lastIndexOf('/');
        l1 = path1.length() - p1;
        l2 = path2.length() - p2;

        // anything with dots voids comparison
        if (l1 > 1 && path1.charAt(p1 + 1) == '.')
            return true;

For instance, this example:
</p>

<pre>
if n%2 == 1 {
	goto L1
}
for n &gt; 0 {
	f()
	n--
L1:
	f()
	n--
}
</pre>

<p>
is erroneous because the label <code>L1</code> is inside
the "for" statement's block but the <code>goto</code> is not.
</p>