* Returns an immutable sorted multiset containing the given elements sorted by their natural
   * ordering.
   *
   * @throws NullPointerException if any element is null
   */
  public static <E extends Comparable<? super E>> ImmutableSortedMultiset<E> of(
      E e1, E e2, E e3, E e4) {
    return copyOf(Ordering.natural(), Arrays.asList(e1, e2, e3, e4));
  }

  /**

   * Returns an immutable sorted multiset containing the given elements sorted by their natural
   * ordering.
   *
   * @throws NullPointerException if any element is null
   */
  public static <E extends Comparable<? super E>> ImmutableSortedMultiset<E> of(
      E e1, E e2, E e3, E e4) {
    return copyOf(Ordering.natural(), Arrays.asList(e1, e2, e3, e4));
  }

  /**

        try (final ResponseData responseData = storageClient.doGet("storage://fess/")) {
            fail();
        } catch (ChildUrlsException e) {
            String[] values = e.getChildUrlList().stream().map(d -> d.getUrl()).sorted().toArray(n -> new String[n]);
            assertEquals(3, values.length);
            assertEquals("storage://fess/dir1/", values[0]);
            assertEquals("storage://fess/dir3/", values[1]);

		}
		if val == "" {
			canonicalQueries = append(canonicalQueries, key)
			continue
		}
		canonicalQueries = append(canonicalQueries, key+"="+val)
	}

	// The queries will be already sorted as resourceList is sorted, if canonicalQueries
	// is empty strings.Join returns empty.
	canonicalQuery := strings.Join(canonicalQueries, "&")
	if canonicalQuery != "" {
		return encodedResource + "?" + canonicalQuery
	}

   * asList()} view.
   *
   * <p><b>Java 8+ users:</b> If you want to convert a {@link java.util.stream.Stream} to a sorted
   * {@code ImmutableList}, use {@code stream.sorted().collect(toImmutableList())}.
   *
   * @throws NullPointerException if any element in the input is null
   * @since 21.0
   */

  /**
   * Searches the specified list for the specified object using the binary search algorithm. The
   * list must be sorted into ascending order according to the specified comparator (as by the
   * {@link Collections#sort(List, Comparator) Collections.sort(List, Comparator)} method), prior to
   * making this call. If it is not sorted, the results are undefined.
   *

        try (final ResponseData responseData = s3Client.doGet("s3://fess/")) {
            fail();
        } catch (ChildUrlsException e) {
            String[] values = e.getChildUrlList().stream().map(d -> d.getUrl()).sorted().toArray(n -> new String[n]);
            assertEquals(3, values.length);
            assertEquals("s3://fess/dir1/", values[0]);
            assertEquals("s3://fess/dir3/", values[1]);

 * Double#NaN NaN}. (This is the one occasion when the behaviour is not the same as you'd get from
 * sorting with {@link java.util.Arrays#sort(double[]) Arrays.sort(double[])} or {@link
 * java.util.Collections#sort(java.util.List) Collections.sort(List<Double>)} and selecting
 * the required value(s). Those methods would sort {@link Double#NaN NaN} as if it is greater than
 * any other value and place them at the end of the dataset, even after {@link

        out.print("<a class=\"sort\" style=\"width: " + maxLen + ";\" href=\"?fmt=detail&sort=name\">Name</a>");
        out.println("<a class=\"sort\" href=\"?fmt=detail&sort=size\">Size</a>");
        out.println("<a class=\"sort\" href=\"?fmt=detail&sort=type\">Type</a>");
        out.println("<a class=\"sort\" style=\"width: 180\" href=\"?fmt=detail&sort=date\">Modified</a><br clear='all'><p>");

                            .sorted((a, b) -> Long.compare(b.frequency, a.frequency))
                            .limit(5)
                            .collect(Collectors.toList());

                    return new GroupAnalysis(
                            groupName, paths, totalUnique, totalOccurrences, totalMemory, totalSavings, topValues);
                })