* rangeSet.add(Range.closedOpen(15, 20)); // connected range; {[1, 10], [11, 20)}
 * rangeSet.add(Range.openClosed(0, 0)); // empty range; {[1, 10], [11, 20)}
 * rangeSet.remove(Range.open(5, 10)); // splits [1, 10]; {[1, 5], [10, 10], [11, 20)}
 * }
 *
 * <p>Note that the behavior of {@link Range#isEmpty()} and {@link Range#isConnected(Range)} may not

     * but overlapping ranges will cause an exception when {@link #build()} is called.
     *
     * @throws IllegalArgumentException if {@code range} is empty
     */
    @CanIgnoreReturnValue
    public Builder<C> add(Range<C> range) {
      checkArgument(!range.isEmpty(), "range must not be empty, but was %s", range);
      ranges.add(range);

   * also be called their <i>union</i>. If they are not, note that the span might contain values
   * that are not contained in either input range.
   *
   * <p>Like {@link #intersection(Range) intersection}, this operation is commutative, associative
   * and idempotent. Unlike it, it is always well-defined for any two input ranges.
   */
  public Range<C> span(Range<C> other) {

      for (Range<Integer> range2 : RANGES) {
        for (Range<Integer> range3 : RANGES) {
          Map<Integer, Integer> model = new HashMap<>();
          putModel(model, range1, 1);
          putModel(model, range2, 2);
          putModel(model, range3, 3);
          RangeMap<Integer, Integer> test = TreeRangeMap.create();
          RangeMap<Integer, Integer> test2 = TreeRangeMap.create();

    return copyOf(TreeRangeSet.create(ranges));
  }

  ImmutableRangeSet(ImmutableList<Range<C>> ranges) {
    this(ranges, /* complement= */ null);
  }

  private ImmutableRangeSet(
      ImmutableList<Range<C>> ranges, @Nullable ImmutableRangeSet<C> complement) {
    this.ranges = ranges;
    this.complement = complement;
  }

  private final transient ImmutableList<Range<C>> ranges;

   * also be called their <i>union</i>. If they are not, note that the span might contain values
   * that are not contained in either input range.
   *
   * <p>Like {@link #intersection(Range) intersection}, this operation is commutative, associative
   * and idempotent. Unlike it, it is always well-defined for any two input ranges.
   */
  public Range<C> span(Range<C> other) {

     * Associates the specified range with the specified value.
     *
     * @throws IllegalArgumentException if {@code range} is empty
     */
    @CanIgnoreReturnValue
    public Builder<K, V> put(Range<K> range, V value) {
      checkNotNull(range);
      checkNotNull(value);
      checkArgument(!range.isEmpty(), "Range must not be empty, but was %s", range);
      entries.add(immutableEntry(range, value));
      return this;

        new RegularImmutableSortedSet<>(ranges, rangeLexOrdering());
    return new ImmutableSortedMap<>(rangeSet, values);
  }

  @Override
  public ImmutableMap<Range<K>, V> asDescendingMapOfRanges() {
    if (ranges.isEmpty()) {
      return ImmutableMap.of();
    }
    RegularImmutableSortedSet<Range<K>> rangeSet =
        new RegularImmutableSortedSet<>(ranges.reverse(), Range.<K>rangeLexOrdering().reverse());

  @Override
  public boolean encloses(Range<C> range) {
    checkNotNull(range);
    Entry<Cut<C>, Range<C>> floorEntry = rangesByLowerBound.floorEntry(range.lowerBound);
    return floorEntry != null && floorEntry.getValue().encloses(range);
  }

  private @Nullable Range<C> rangeEnclosing(Range<C> range) {
    checkNotNull(range);
    Entry<Cut<C>, Range<C>> floorEntry = rangesByLowerBound.floorEntry(range.lowerBound);

     *         specified version range.
     *         <p>
     *         The restrictions of the returned version range will be an intersection of the restrictions
     *         of this version range and the specified version range if both version ranges have
     *         restrictions. Otherwise, the restrictions on the returned range will be empty.
     *         </p>
     *         <p>